Question

1. When the Kelvin temperature of an enclosed gas doubles, the particles of the gas ____. (1 point)

Answer 1

Answer 1 : The correct option is, move faster

Explanation :

As we know that the kinetic energy of the particle of the gas is directly proportional to the temperature of the gas. That means higher the temperature higher will be the kinetic energy.

When the Kelvin temperature of an enclosed gas doubles, the kinetic energy will be double and then the particles of the gas move faster.

Answer 2 : The correct option is, It increases by a factor of eight.

Explanation :

According to the Boyle's law, the volume of the gas is inversely proportional to the pressure of the gas at constant temperature and the number of moles of gas.

$\frac{P_{final}}{P_{initial}}=\frac{V_{initial}}{V_{final}}$

$\frac{P_{final}}{P_{initial}}=\frac{4L}{0.5L}=8$

Hence, the gas pressure change increases by a factor of eight.

Answer 3 : The correct option is, the volume of a gas is directly proportional to its temperature in kelvins.

According to the Charles's law, the volume of the gas is directly proportional to the temperature of the gas at constant pressure and the number of moles of gas.

$V\propto T$

$\frac{V}{T}=k$

Answer 4 : The correct option is, 36 ml

Solution : Given,

initial volume = 17 ml

initial temperature = $-112^oC=273+(-112)=161K$

final temperature = $70^oC=273+70=343K$

Formula used : $\frac{V_{final}}{V_{initial}}=\frac{T_{final}}{T_{initial}}$

$\frac{V_{final}}{17ml}=\frac{343K}{161K}$

$V_{final}=36ml$

Therefore, the volume of the sample occupy at $70^oC$ is, 36 ml

Answer 5 : The correct option is, temperature, pressure, and volume

Explanation :

Combined gas law is the combination of the Boyle's law, Charles's law and Gay Lussac's law at constant number of moles of gas.

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

The variable used in the combined gas law are temperature, pressure, and volume .

Answer 2

1) Answer:

a) move faster

Explanation:

Kinetic energy KE of gas particles  is related to temperature T as:

$KE = \frac{3}{2} kT$

where k = Boltzmann constant

Therefore, as T doubles the KE will also double and the gas particles will begin to move faster.

2) Answer:

C) It increases by a factor of eight.

Explanation:

As per Boyle's law, pressure P of a gas is inversely proportional to its volume V

i.e PV = constant

or P1V1 = P2V2 ----(1)

where P1V1 and P2V2 are the initial and final stated pressure and volume respectively

P2/P1 = V1/V2 = 4/0.5 = 8

P2 = 8(P1)

3) Answer:

B) the volume of a gas is directly proportional to its temperature in kelvins

Explanation:

Charles law relates the temperature(T) of a gas to its volume (V) as follows:

V/T  = constant

i.e. volume of a gas is directly proportional to its temperature.

4)Answer:

D) 8.0 ml

Explanation:

Charles law relates the temperature(T) of a gas to its volume (V) as follows:

V/T  = constant

i.e. volume of a gas is directly proportional to its temperature.

V1/T1 = V2/T2

V2 = V1(T2/T1) = 17ml (-112+273)K/(70+273)K= 7.97 ml = 8.0 ml

5) Answer:

D) temperature, pressure, and volume

Explanation:

The combined gas law can be written as:

PV = nRT

where P = pressure, V = volume, n = number of moles

R = gas constant and T = temperature

Hence it relates temperature, pressure and volume