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Alex
3 years ago
6

Consider the following chemical reaction: H2 (g) + I2 (g) 2HI (g) At equilibrium in a particular experiment, the concentrations

of H2, I2, and HI were and respectively. The value of Keq for this reaction is__________.
Chemistry
1 answer:
bearhunter [10]3 years ago
4 0

The question is incomplete, here is the complete question:

Consider the following chemical reaction: H₂ (g) + I₂ (g) ⇔ 2HI (g) At equilibrium in a particular experiment, the concentrations of H₂, I₂, and HI were 0.15 M, 0.033 M and 0.55 M respectively. The value of Keq for this reaction is

<u>Answer:</u> The value of K_{eq} for the given reaction is 61.11

<u>Explanation:</u>

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_[eq}

For a general chemical reaction:

aA+bB\rightarrow cC+dD

The expression for K_{eq} is written as:

K_{eq}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

For the given chemical equation:

H_2(g)+I_2(g)\rightleftharpoons 2HI(g)

The expression of K_{eq} for above equation follows:

K_{eq}=\frac{[HI]^2}{[H_2][I_2]}

We are given:

[HI]_{eq}=0.55M

[H_2]_{eq}=0.15M

[I_2]_{eq}=0.033M

Putting values in above expression, we get:

K_{eq}=\frac{(0.55)^2}{0.15\times 0.033}\\\\K_{eq}=61.11

Hence, the value of K_{eq} for the given reaction is 61.11

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Answer is: <span>he boiling point of a 1.5 m aqueous solution of fructose is </span>100.7725°C.
The boiling point elevation is directly proportional to the molality of the solution according to the equation: ΔTb = Kb · b.<span>
ΔTb -  the boiling point elevation.
Kb - the ebullioscopic constant. of water.
b - molality of the solution.
Kb = 0.515</span>°C/m.
b = 1.5 m.
ΔTb = 0.515°C/m · 1.5 m.
ΔTb = 0.7725°C.
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4 0
3 years ago
Cinnamon owes its flavor and odor to cinnamaldehyde (C9H8O). Determine the boiling point elevation of a solution of 92.7 mg of c
Flauer [41]

Answer:

The boiling point elevation is 3.53 °C

Explanation:

∆Tb = Kb × m

∆Tb is the boiling point elevation of the solution

Kb is the molal boiling point elevation constant of CCl4 = 5.03 °C/m

m is the molality of the solution is given by moles of solute (C9H8O) divided by mass of solvent (CCl4) in kilogram

Moles of solute = mass/MW =

mass = 92.7 mg = 92.7/1000 = 0.0927 g

MW = 132 g/mol

Moles of solute = 0.0927/132 = 7.02×10^-4 mol

Mass of solvent = 1 g = 1/1000 = 0.001 kg

m = 7.02×10^-4 mol ÷ 0.001 kg = 0.702 mol/kg

∆Tb = 5.03 × 0.702 = 3.53 °C (to 2 decimal places)

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djyliett [7]

Answer:

False

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Consisting of parts all of the same kind material.

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Zielflug [23.3K]

Answer:

The correct answer is skeleton equation.

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In chemistry, the skeletal formula of a compound is an abbreviated representation of its molecular structure. Skeleton formulas are used because they clearly show complicated structures, they are fast and simple to draw.

All atoms that are not carbon or hydrogen are represented by their chemical symbol. The relative amounts of reagents and products are not indicated.

Have a nice day!

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2 years ago
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