<u>The Concept:</u>
We are given the density of a sample of the metal = 11.4 grams / cm³
and we need to find the volume occupied by a sample of 30.5 grams
For this solution, we will use dimensional analysis
from the given information, we can also say that the density of the metal is:
1 cm³ / 11.4 grams
If we multiply this value by 30.5 grams, the 'grams' in the numerator and the denominator will cancel out and we will be left with the volume occupied by 30.5 grams of the metal
<u>Solving for the volume:</u>
X 30.5 grams = (30.5 / 11.4) cm³
Volume of 30.5 grams of the sample = 2.68 cm³
Answer: 2 electrons
Explanation: Good luck! :D
Answer:
3HC2H3O2(aq) + Al(OH)3(aq) --> AI(C2H3O2)3(aq) + 3H2O(l)
Explanation:
HC2H3O2 is the chemical formula for Ethanoic acid which can be written as CH3COOH.
Hence, the balanced equation is stated as 3CH3COOH(aq) + Al(OH)3(aq) --> AI(CH3COO)3(aq) + 3H2O(l)
Acid + base → Salt + Water.
The equation is a neutralization reaction in which the acid, aqeous CH3COOH reacts completely with an appropriate amount of base, aqueous Al(OH)3 to produce salt, aqueous AI(CH3COO)3(aq)
and water, liquid H2O only.
During this reaction, the hydrogen ion, H+, from the Ethanoic acid is neutralized by the hydroxide ion, OH-, from the Aluminum hydroxide to form the water molecule, H2O and aluminium ethanoate.
Thus, it is called a neutralization reaction.
Climax (the most exciting or plot changing event)
Answer:
1,763°F
Explanation:
I really cant explain it is a little complicated but there is the answer hope it helped you a lot
