Answer:
B
Step-by-step explanation:
This is because You would still have the Y value as the answer. When you raise a function to the 0 power you will ultimately get on. In this only the coefficient is being raised rather than the whole system.
Answer:
4.4722
Step-by-step explanation:
The following table shows the 36 elements of the sample space of the experiment
![\left[\begin{array}{cccccccc}&1&2&3&4&5&6\\--&--&--&--&--&--&--\\1\;|&1&2&3&4&5&6\\2\;|&2&2&3&4&5&6\\3\;|&3&3&3&4&5&6\\4\;|&4&4&4&4&5&6\\5\;|&5&5&5&5&5&6\\6\;|&6&6&6&6&6&6\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccccccc%7D%261%262%263%264%265%266%5C%5C--%26--%26--%26--%26--%26--%26--%5C%5C1%5C%3B%7C%261%262%263%264%265%266%5C%5C2%5C%3B%7C%262%262%263%264%265%266%5C%5C3%5C%3B%7C%263%263%263%264%265%266%5C%5C4%5C%3B%7C%264%264%264%264%265%266%5C%5C5%5C%3B%7C%265%265%265%265%265%266%5C%5C6%5C%3B%7C%266%266%266%266%266%266%5Cend%7Barray%7D%5Cright%5D)
From this table we can compute the probabilities
:
P(X = 1) = 1/36
P(X = 2) = 3/36
P(X = 3) = 5/36
P(X = 4) = 7/36
P(X = 5) = 9/36
P(X = 6) = 11/36
So the expected value equals
1P(X=1)+2P(X=2)+3P(X=3)+4P(X=4)+5P(X=5)+6P(X=6) =
= 1/36 + 6/36 + 15/36 + 28/36 + 45/36 + 66/36 = 161/36 =
4.4722
Answer:
1.
Vert. asymptote: x = {-3, 2}
Horiz. asymptote: y = 0
x-int: None
Question 3.
a. There is no hole
b. Vert. asymptote: x = {-2, 2}
c. f(x) = 0: x = {0, -1/2}
d. The graph has no hole at (-2, 4)
Question 4.
a. Vert. asymptote: x = {-2, 2}
b. f(x) = 0: x = {0, -1/2}
c. Horizontal asymptote: y = 2
d. The graph has no hole
I'm a bit confused. Some of the things stated in the question aren't true like how there are holes in places where there aren't.
Slope: (y2-y1)/(x2-x1)
Points given: (-4,1) and (1,-2)
(-2-1)/(1+4) = -3/5
Answer: the slope is -3/5
1/2r - 3 = 3(4-3/2) -----> Simplify the right side.
1/2r - 3 = 3(1/2) -----> Multiply
1/2r - 3 = 3/2 ----> Add 3 to both sides
1/2r = 6/2 + 3/2
1/2r = 9/2 -----> Divide both sides by 1/2 which is the same as multiplying my 2
r = 18/2
r = 9
Hope this helps!
