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dlinn [17]
3 years ago
9

In which quadrant on a coordinate plane are both coordinates negative?

Mathematics
2 answers:
guajiro [1.7K]3 years ago
8 0

Answer:

C) Quadrant III

Step-by-step explanation:

Leona [35]3 years ago
3 0

Answer:

i am positive the answer is C

Step-by-step explanation:

hope this helps....also pls give meh brainliest if u can

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To estimate the quotient 98.3 divides by 52.6 Brady used compatible numbers 100 dived by 5 =20. Is his estimate reasonable ? Exp
marissa [1.9K]
No, not reasonable.

98.3 divides by 52.6

Brady used compatible numbers 100 divided by 5 =20

He should've used 100 divided by 50 = 2
7 0
4 years ago
Ms. Potts washed 1/4 of her laundry. Her son washed 3/7 of it. Who washed most of the laundry? How much of the laundry still nee
LenaWriter [7]

Answer:

  • Son washed more
  • Remaining 9/28 of the laundry

Step-by-step explanation:

<u>Make denominators common to see the difference in fractions:</u>

  • 1/4 = 7/28
  • 3/7 = 12/28

Son washed more laundry as 12/28 > 7/28

<u>Together they washed:</u>

  • 7/28 + 12/28 = 19/28 of the laundry

<u>Remaining part is:</u>

  • 1 - 19/28 =
  • 28/28 - 19/28 =
  • 9/28 of the laundry
7 0
3 years ago
Read 2 more answers
Expand the following using the Binomial Theorem and Pascal’s triangle. (x + 2)6 (x − 4)4 (2x + 3)5 (2x − 3y)4 In the expansion o
ivolga24 [154]
\bf (2x+3)^5\implies &#10;\begin{array}{llll}&#10;term&coefficient&value\\&#10;-----&-----&-----\\&#10;1&&(2x)^5(+3)^0\\&#10;2&+5&(2x)^4(+3)^1\\&#10;3&+10&(2x)^3(+3)^2\\&#10;4&+10&(2x)^2(+3)^3\\&#10;5&+5&(2x)^1(+3)^4\\&#10;6&+1&(2x)^0(+3)^5&#10;\end{array}

as you can see, the terms exponents, for the first term, starts at highest, 5 in this case, then every element it goes down by 1, till it gets to 0

for the second term, starts at 0, and every element it goes up by 1, till it gets to the highest

now, to get the coefficient, they way I get it, is "the product of the current coefficient and the exponent of the first term, divided by the exponent of the second term plus 1"

notice the first coefficient is always 1

so...how did we get 10 for the 3rd element?  well, 5*4/2
how did we get 10 for the fourth element?  well, 10*2/4


\bf (2x-3y)^4\implies &#10;\begin{array}{llll}&#10;term&coefficient&value\\&#10;-----&-----&-----\\&#10;1&&(2x)^4(-3y)^0\\&#10;2&+4&(2x)^3(-3y)^1\\&#10;3&+6&(2x)^2(-3y)^2\\&#10;4&+4&(2x)^1(-3y)^3\\&#10;5&+1&(2x)^0(-3y)^4&#10;\end{array}


\bf (3a+4b)^8\implies &#10;\begin{array}{llll}&#10;term&coefficient&value\\&#10;-----&-----&-----\\&#10;1&&(3a)^8(+4b)^0\\&#10;2&+8&(3a)^7(+4b)^1\\&#10;3&+28&(3a)^6(+4b)^2\\&#10;4&+56&(3a)^5(+4b)^3\\&#10;5&+70&(3a)^4(+4b)^4\\&#10;6&+56&(3a)^3(+4b)^5\\&#10;7&+28&(3a)^2(+4b)^6\\&#10;8&+8&(3a)^1(+4b)^7\\&#10;9&+1&(3a)^0(+4b)^8&#10;\end{array}

and from there, you can simplify the elements of the expansion by combining the coefficients

like for example, the 7th element of (3a+4b)⁸ will then be 1032192a²b⁶
7 0
3 years ago
Read 2 more answers
Which two values of x are roots of the polynomial below? x2 + 3x - 5
lesya692 [45]

Answer:

Step-by-step explanation:

The roots are the values of x for which x² + 3x - 5 = 0.

Quadratic formula:

x = [-3±√(3²-4(1)(-5))]/(2·1) = [-3±√29]/2

3 0
3 years ago
Determine the translation
arsen [322]

Answer:

<em>1 unit left and 7 units up</em>

Step-by-step explanation:

|3 - 2| = |1| = 1

The x-coordinate when from 3 to 2, so it is 1 unit left.

|-4 - 3| = |7| = 7

The y-coordinate when from -4 to 3, so it is 7 units up.

7 0
3 years ago
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