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2 years ago

Dylan started to write the expanded form of 3,687.89 as shown below.

Mathematics

2 answers:

ELEN [110]2 years ago

4 0

Answer:

Answer: A. 8×100+8×(1100)

Step-by-step explanation:

before removing the 0 from 1000, we got to add 100 and 1,000. then we remove the 0.

hope this helped.

Mnenie [13.5K]2 years ago

4 0

The correct answer is A

Brainliest?

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I need help or the answer

loris [4]

Answer:

5x+4y = 52

Step-by-step explanation:

We can first write the equation in point slope form

y-y1 = m(x-x1) where m is the slope and (x1,y1) is the point

y - 8 = -5/4 ( x-4)

Multiply each side by 4 to get rid of the fraction

4(y - 8) = 4*(-5/4) ( x-4)

4(y - 8) = -5 ( x-4)

Distribute

4y - 32 = -5x+20

We want the equation in the form

Ax + By = C

Add 5x to each side

5x+4y -32 = -5x+5x+20

Add 32 to each side

5x+4y -32+32 =32+20

5x+4y = 52

4 0

3 years ago

Help with this question, please!!

olga2289 [7]

Answer: D

Step-by-step explanation:

You need a calculator for this cause the numbers are really large. I used a fx-9860GII Casio calculator. I put the equations on the graph mode. And then I got the x➡️0 for both equations.

I got x=0, y=5000 for the first equation

x=0, y=5200 for the new one.

You can see the y is (5200-5000)=200 more than the old equation. As the x is 0 for both that means the new one moved 200 up for the new one. It goes up cause its positive number .

I put the pictures so you can understand what I'm saying.

8 0

3 years ago

URGENT HELP ME PLEASE

Trava [24]

Answer:

(a) $\log_3(\dfrac{81}{3})=3$

(b) $\log_5(\dfrac{625}{25})=2$

(d) $\log_4(\dfrac{64}{16})=1$

(e) $\log_6(36^4)=8$

(f) $\log(100^3)=6$

Step-by-step explanation:

Let as consider the given equations are $\log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?$ .

(a)

$\log_3(\dfrac{81}{3})=\log_3(27)$

$\log_3(\dfrac{81}{3})=\log_3(3^3)$

$\log_3(\dfrac{81}{3})=3$ $[\because \log_aa^x=x]$

(b)

$\log_5(\dfrac{625}{25})=\log_5(25)$

$\log_5(\dfrac{625}{25})=\log_5(5^2)$

$\log_5(\dfrac{625}{25})=2$ $[\because \log_aa^x=x]$

(c)

$\log_2(\dfrac{64}{8})=\log_2(8)$

$\log_2(\dfrac{64}{8})=\log_2(2^3)$

$\log_2(\dfrac{64}{8})=3$ $[\because \log_aa^x=x]$

(d)

$\log_4(\dfrac{64}{16})=\log_4(4)$

$\log_4(\dfrac{64}{16})=1$ $[\because \log_aa^x=x]$

(e)

$\log_6(36^4)=\log_6((6^2)^4)$

$\log_6(36^4)=\log_6(6^8)$

$\log_6(36^4)=8$ $[\because \log_aa^x=x]$

(f)

$\log(100^3)=\log((10^2)^3)$

$\log(100^3)=\log(10^6)$

$\log(100^3)=6$ $[\because \log10^x=x]$

5 0

3 years ago

On a piece of paper, use a protractor to construct △ABC with m∠A=30° , m∠B=60° , and m∠C=90° .

pochemuha

Answer:

It's a right triangle.

Step-by-step explanation:

△ABC with m∠A=30° , m∠B=60° , and m∠C=90°

It's a right triangle.

6 0

3 years ago

Could someone please explain/help me to do this using Pythagoras theorem?

alex41 [277]

Answer:

$\boxed{478.02}$

Step-by-step explanation:

→ First understand what Pythagoras theorem is

Pythagoras is a theorem used to find the hypotenuse (the side opposite to the right-angle) of a triangle. We would need the base lengths as well the height in order to use Pythagoras.

→ State the formula and identify the letters

a² + b² = c² ⇒ where 'a' is 380cm, 'b' is 290cm and 'c' is what we are trying to work out

→ Substitute in the values into the formula

380² + 290² = c²

⇒ Simplify

144400 + 84100 = c²

⇒ Collect the numbers together

228500 = c²

⇒ Square root both sides to find 'c'

478.0167361 = c

→ The length of the diagonal is 478.02

8 0

3 years ago