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lions [1.4K]
3 years ago
6

Choose the point on the terminal side of 135°.

Mathematics
2 answers:
ivanzaharov [21]3 years ago
8 0
Correct answer is C. (-1, 1)

Hope it helps
natulia [17]3 years ago
5 0

Answer:

The correct option is C. The point on the terminal side of 135° is (-1,1).

Step-by-step explanation:

The point must be lies on the second quadrant because terminal angle is 135°.

Let the required point be (x,y).

\tan\theta=\frac{y}{x}

\tan(135^{\circ})=\frac{y}{x}

\tan(90^{\circ}+45^{\circ})=\frac{y}{x}

Using quadrant concepts, above equation can be written as

-\cot(45^{\circ})=\frac{y}{x}           [\because \cot 45^{\circ}=1]          

-1=\frac{y}{x}                          ..... (1)

In option A,

\frac{y}{x}=\frac{\sqrt{3}}{-1} =-\sqrt{3}\neq -1

In option B,

\frac{y}{x}=\frac{1}{-\sqrt{3}} =-\frac{1}{\sqrt{3}}\neq -1

In option C,

\frac{1}{-1}=-1

Therefore option C is correct.

In option B,

\frac{y}{x}=\frac{1}{\sqrt{3}} =\frac{1}{\sqrt{3}}\neq -1.

Therefore correct option is C. The point on the terminal side of 135° is (-1,1).

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