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PtichkaEL [24]
3 years ago
10

Suppose you have a gift certificate worth $20 for one long-distance phone call. If the charge is $1.10 for the first minute and

$0.42 for each additional minute, what is the longest that you can talk?
Mathematics
2 answers:
liberstina [14]3 years ago
4 0
You subtract i think
Alexxx [7]3 years ago
4 0

Answer:

46 minutes.

Step-by-step explanation:

You have a gift certificate worth $20 for one long-distance phone call.

The charge for the first minute = $1.10

Let the other additional minutes that you can talk = x

The charges for the x minutes = 0.42 per minute

the equation will be : 1.10 + 0.42x = 20

0.42x = 20 - 1.10

0.42x = 18.90

x = \frac{18.90}{0.42}

x = 45

1 minute for $1.10 + 45 minutes for $0.42/min.

you can talk for 46 minutes.

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Given that set A has 48 elements and set B has 21 elements, determine each of the following. (a) The maximum possible number of
yKpoI14uk [10]

Answer:  The required answers are

(a) 69,  (b) 21,  (c) 21  and  (d) 0.

Step-by-step explanation:  We are given that the set A has 48 elements and the set B has 21 elements.

(a) To determine the maximum possible number of elements in A ∪ B.

If the sets A and B are disjoint, that is they do not have any common element. Then, A ∩ B = { }   ⇒   n(A ∩ B) = 0.

From set theory, we have

n(A\cup B)=n(A)+n(B)-n(A\cap B)=48+21-0=69.

So, the maximum possible number of elements in  A ∪ B is 69.

(b) To determine the minimum possible number of elements in A ∪ B.

If the set B is a subset of set A, that is all the elements of set B are present in set A. Then,  n(A ∩ B) = 21.

From set theory, we have

n(A\cup B)=n(A)+n(B)-n(A\cap B)=48+21-21=48.

So, the minimum possible number of elements in  A ∪ B is 21.

(c) To determine the maximum possible number of elements in A ∩ B.

If the set B is a subset of set A, that is all the elements of set B are present in set A. Then, n(A ∩ B) = 21.

So, the maximum possible number of elements in  A ∩ B is 21.

(d) To determine the minimum possible number of elements in A ∩ B.

If the sets A and B are disjoint, that is there is no common element in the sets A and B . Then,  n(A ∩ B) = 0.

So, the maximum possible number of elements in  A ∩ B is 0.

Thus, the required answers are

(a) 69,  (b) 21,  (c) 21  and  (d) 0.

6 0
2 years ago
What is the length of a hypotenuse of a triangle if each of its legs is 4 units
azamat

Answer:

\boxed{c = 5.7 units}

Step-by-step explanation:

<u><em>Using Pythagorean Theorem:</em></u>

=> c^2 = a^2+b^2

Where c is hypotenuse, a is base and b is perpendicular and ( a, b = 4)

=> c^2 = 4^2+4^2

=> c^2 = 16+16

=> c^2 = 32

Taking sqrt on both sides

=> c = 5.7 units

8 0
2 years ago
Read 2 more answers
Y-9=26<br> Can anyone help me with this question
statuscvo [17]

Answer:

Y = 35

Step-by-step explanation:

6 0
2 years ago
What is the answer for (a^2+12c)÷7b-1
vodomira [7]

Answer:

Step-by-step explanation:

Integer roots:

a = 6 n + 1, b = 7, c = -3 n^2 - n, n element Z

a = 6 n + 5, b = 7, c = -3 n^2 - 5 n - 2, n element Z

Derivative:

d/da(1/7 (a^2 + 12 c) b - 1) = (2 a b)/7

Indefinite integral:

integral(-1 + 1/7 b (a^2 + 12 c)) da = (a^3 b)/21 + (12 a b c)/7 - a + constant

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5 0
2 years ago
What is the area of the unshaded path
andre [41]

Answer:

114 feet

Step-by-step explanation:

the black and white will both have the same area. and given that each path is 1 ft wide and initially 12 ft long we can slowly determine the area.

x times 1 will still equal x

12(1) still equals 12 so we can just write it as 12.

12+12+11+11+10+10+9+9+8+8+7+7= 114

where I came up with this? there are a total of 12 sides if you follow the black path. and by every 2 sides the path gets shorter by 1 foot.

the white side also has 12 sides if you look. therefore both the black and the white part of the shape will have an area of 114.

7 0
2 years ago
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