Question

A titration is carried out to determine the concentration of the acid in an old bottle of aqueous HCl whose label has become unreadable.What is the HCl concentration if 32.1mL of 0.250M NaOH is required to titrate a 30.0mL sample of the acid?

Answer 1

Answer:

The concentration of HCl is - 0.2675 M

Explanation:

At equivalence point ,

Moles of $HCl$ = Moles of NaOH

Considering :-

$Molarity_{HCl}\times Volume_{HCl}=Molarity_{NaOH}\times Volume_{NaOH}$

Given  that:

$Molarity_{NaOH}=0.250\ M$

$Volume_{NaOH}=32.1\ mL$

$Volume_{HCl}=30.0\ mL$

$Molarity_{HCl}=?\ M$

So,  

$Molarity_{HCl}\times Volume_{HCl}=Molarity_{NaOH}\times Volume_{NaOH}$

$Molarity_{HCl}\times 30.0=0.250\times 32.1$

$Molarity_{HCl}=\frac{0.250\times 32.1}{30.0}=0.2675\ M$

The concentration of HCl is - 0.2675 M