When the phenol shown below is treated with KOH, it forms a product whose IR spectrum does not show an absorption in the 3200-36
00 cm-1 region. Propose a structure for the product.?
1 answer:
Answer:
Explanation:
The first attached diagram shows the proposed phenol that is being treated with KOH to form Oxonine (CₐHₐO).
Reaction of Arylhalide after treatment with KOH lead to the displacement of Bromine atom with the hydrogen from the hydroxyl (OH) substituent , then forming HBr , leaving the oxy (-O) atom alone to form an Oxonine compound.
Therefore the propose structure for the product (Oxonine) CₐHₐO is shown in the second diagram attached below.
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