Answer:

Step-by-step explanation:
Given
-- Objective function
Constraints:



Required
Minimum value of E
To do this, we apply graphical method
See attachment for plots of
and 
From the attached plot, the point that satisfy
is:

So, we have:

This gives:



Answer:
67.3%
Step-by-step explanation:
Calculate profit = selling price - cost price
cost price = 50 × $28 = $1400
38 × $49 = $1862
12 × $40 = $480
selling price = $1862 + $480 = $2342
Profit = $2342 - $1400 = $942
% profit =
× 100%
=
× 100% ≈ 67.3% ( to 1 dec. place )
The answer is C: first add 2 both sides then divide both sides by -5.
1. Rational/The sum of two rationals is always rational
2. Irrational/ the sum of a rational and an irrational is always irrational
3. Irrational/The product of a nonzero rational and an irrational is always irrational
4. Rational/The product of two rationals is always rational
Pretty much all the irrational numbers are the ones with radical signs over them and the rational numbers are the fractions and whole numbers. Once you identify the two numbers to be rational or irrational, you can then find your answer within the second part of the answers.