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olga55 [171]
2 years ago
8

8, 12, 16,... Find the 31st term.

Mathematics
2 answers:
Ainat [17]2 years ago
7 0
<h2>8, 12, 16,...</h2><h2>Find the 31st term.</h2><h3>352</h3>

<em>Hope I helped.  :)</em>

<em />

<em>- Valenteer</em>

hoa [83]2 years ago
6 0
The answer to this question is 124
Hope this helped:)
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What is the solution to he equation (y/y-4)-(4/y+4)=3^2/y^2-16
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Answer:

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Step-by-step explanation:

Given equation is \frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}

Factor denominators then solve by making denominators equal

\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}

\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}

\frac{y\left(y+4\right)-4\left(y-4\right)}{\left(y-4\right)\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}

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lbvjy [14]

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