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Alchen [17]
3 years ago
9

You are new in town and need to know how the streets flow in order to efficiently get around town. Your math friend decides to

Mathematics
1 answer:
BartSMP [9]3 years ago
7 0

Answer:

  1. The Fire Department and the School
  2. The Fire Department and the Hospital.

Step-by-step explanation:

On the matrix, a 1 represent the existence of a street between two buildings while a 0 indicates the absence of a street between any two building.

Let:

  • F represent the Fire department
  • S represent the School
  • H represent the Hospital
  • A represent the Apartment Building.

The heading by the side of the matrix is the <em>ith</em> entry while the headings on top is the <em>jth</em> entry. Movement is from ith position to jth position.

From the given matrix, the directed graph is presented in the attachment below.

From the graph, the following buildings have two-way streets between them.

  1. The Fire Department and the School
  2. The Fire Department and the Hospital.

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3x 2y = 4 2x - y = 5 this system of equations has no solution. has one solution. is coincident.
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Is is square root of 1.6875 a rational number
mamaluj [8]

<em><u>Question:</u></em>

Is square root of 1.6875 a rational number ?

<em><u>Answer:</u></em>

Square root of 1.6875 a rational number is not a rational number

<em><u>Solution:</u></em>

Given that we have to find square root of 1.6875 and determine if it is rational number or not

Let us first find square root of 1.6875

\sqrt{1.6875} = 1.29903810568

Let us understand about rational number

A rational number is a number that can be expressed as a fraction (ratio) in the form \frac{p}{q} where p and q are integers and q is not zero.

When a rational number fraction is divided to form a decimal value,  it becomes a terminating or repeating decimal.

So the number 1.29903810568 is not a rational number

<em><u>In other words we can say,</u></em>

Only the square roots of square numbers are rational. Here 1.6875 is not a perfect square. So it is not rational number

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