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saw5 [17]
4 years ago
13

Please help me answer this question.

Mathematics
1 answer:
Studentka2010 [4]4 years ago
3 0
The only difference here is the angles.
x = 3cos t
x = 3cos 4t
Same for the two equations.
There is a compound angle (4t)

Hope ot helped!
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Write a plan to prove that ∠1≅∠2.
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Step-by-step explanation:

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(a) The perimeter of a rectangular field is 310 m.
Softa [21]

Answer:

<h3 />

a. \boxed{ \bold{ \boxed{ \sf{width \: of \: rectangular \: field \:  = 71 \: meter}}}}

b. \boxed{ \bold{ \boxed{ \sf{length \: of \: rectangular \: painting \:  = 85 \: cm}}}}

Step-by-step explanation:

a. Given,

Perimeter of rectangular field ( P ) = 310 m

Length of the field ( L ) = 84 m

Width of the field ( W ) = ?

<u>Finding </u><u>the </u><u>width </u><u>of </u><u>the </u><u>rectangular</u><u> </u><u>field</u>

\boxed{ \sf{perimeter \: of \: rectangle = 2(l + w)}}

plug the values

⇒\sf{310 = 2(84 + w)}

Distribute 2 through the parentheses

⇒\sf{310 = 168 + 2w}

Swap the sides of the equation

⇒\sf{168 + 2w = 310}

Move 168 to right hand side and change it's sign

⇒\sf{2w = 310 - 168}

Subtract 168 from 310

⇒\sf{2w = 142}

Divide both sides of the equation by 2

⇒\sf{ \frac{2w}{2}  =  \frac{142}{2} }

Calculate

⇒\sf{w = 71 \: m}

Width = 71 meters

------------------------------------------------------------

2. Given,

Area of rectangular painting ( A ) = 5185 cm²

Width of the painting ( w ) = 61 cm

Length of the painting ( l ) = ?

<u>Finding </u><u>length </u><u>of </u><u>the </u><u>painting</u>

\boxed{ \sf{area \: of \: rectangle = l \times w}}

plug the values

⇒\sf{5185 = 61l}

Swap the sides of the equation

⇒\sf{61 \: l \:  = 5185}

Divide both sides of the equation by 61

⇒\sf{ \frac{61 \: l}{61}  =  \frac{5185}{61} }

Calculate

⇒\sf{l = 85} cm

Length = 85 cm

Hope I helped!

Best regards !!!

4 0
3 years ago
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