2 years ago

Help...,..........please..............

1 answer:

5 0

Here, Add both the equations in order to eliminate y,
5x = 10
x = 10/5
x = 2

Now, substitute it in 1st equation,
8(2) - 4y = -32
-4y= -32- 16
y = -48/-4
y = 12

In short, Your Answer would be (2, 12)

Hope this helps!

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What is the inverse of f(x)=3x+6 ?

scZoUnD [109]

Answer:

$\boxed{\sf \ \ f^{-1}(x)=\dfrac{x-6}{3} \ \ }$

Step-by-step explanation:

hello,

we can write

$fof^{-1}(x)=x \ and \ fof^{-1}(x)=f(f^{-1}(x))=3f^{-1}(x)+6 \ so\\3f^{-1}(x)+6=x \ \ subtract \ 6\\3f^{-1}(x)=x-6 \ \ divide \ \ by \ \ 3\\ f^{-1}(x)=\dfrac{x-6}{3}$

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3 0

3 years ago

Please find the square roots of the following complex number.

Nana76 [90]

Hey there,

First, find the square root of the given equation.

$\sqrt{z}=\sqrt{81(\text{cos}(\frac{4\pi}{9})+i\text{sin}(\frac{4\pi}{9})}\\=9\text{cos}\frac{1}{2}(2k\pi+(\frac{4\pi}{9}))+i\text{sin}\frac{1}{2} (2k\pi+(\frac{4\pi}{9}))$

Keep in mind that this is solved for k = 0 and 1.

Second, simplify.

$=9\text{cos}(\frac{2\pi}{9})+i\text{sin}(\frac{2\pi}{9})~\text{or}~9\text{cos}(\frac{11\pi}{9})+i\text{sin}(\frac{11\pi}{9})$

Best of Luck!

6 0

2 years ago

4<br> The points (2, r) and (4, -8) lie on a line with slope - 1. Find the missing coordinate r.

maksim [4K]

R=-6

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6 0

2 years ago

<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B%2013x%3D%20-6" id="TexFormula1" title="x^{2} + 13x= -6" alt="x^{2} + 13x= -6

HACTEHA [7]

Answer:

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Step-by-step explanation:

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2 years ago

Use a geometric formula to solve the problem. A rectangle has a width of 4 centimeters and a perimeter of 26 centimeters. Find t

AURORKA [14]

The length is 9.

The formula to find the perimeter of a rectangle is

2L + 2W = P.

2L + 2(4) = 26.

2L + 8 = 26.

2L + 8 (-8) = 26 (-8).

2L = 18.

2L/2 = 18/2.

L = 9.

8 0

3 years ago