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kobusy [5.1K]
3 years ago
11

A metal wire is in thermal contact with two heat reservoirs at both of its ends. Reservoir 1 is at a temperature of 563 K, and r

eservoir 2 is at a temperature of 354 K. Compute the total change in entropy arising from the conduction of 1760 J of heat through the wire. Please give your answer in units of J/K.
Physics
1 answer:
Schach [20]3 years ago
8 0

Answer:

1.85 J/K

Explanation:

The computation of total change in entropy is shown below:-

Change in Entropy = Sum Q ÷ T

= \frac{-heat\ entering\ the\ reservoir}{Reservoir\ 1\ Temperature} + \frac{Conduction\ of\ heat}{Reservoir\ 2\ Temperature}

= \frac{-1760}{563} + \frac{1760}{354}

= -3.12 + 4.97

= 1.85 J/K

Therefore for computing the total change in entropy we simply applied the above formula.

As we can see that there is heat entering the reservoir so it will be negative while cold reservoir will be positive else the process would be impossible.

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avanturin [10]

Answer:

add them together then they

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2 years ago
if a sine wave representing ac voltage has an effective value of 70 vac what would be the waves peak value​
Morgarella [4.7K]

Answer:

99 V

Explanation:

The effective voltage of an AC current (also called rms voltage) is given by

V_{rms} = \frac{V_0}{\sqrt{2}}

where

Vrms is the rms voltage

V0 is the peak voltage

In this problem, we know the effective voltage:

V_{rms} = 70 V

Therefore, we can re-arrange the equation to find the peak voltage:

V_0 = V_{rms} \sqrt{2} =(70 V)(\sqrt{2})=99 V

3 0
3 years ago
Example 2.13 The acceleration a of a particle in a time t is given by the equation a = 2+ 5t^2. Find the instantaneous velocity
Serhud [2]

Answer:

the instantaneous velocity is 51 m/s

Explanation:

Given;

acceleration, a = 2 + 5t²

Acceleration is the change in velocity with time.

a = \frac{dv}{dt} \\\\a = 2 + 5t^2\\\\The \ acceleration \ (a) \ is \ given \ so \ we \ have \ to \ find \ the \ velocity \ (v)\\\\To \ find \ the \ velocity, \ integrate\ both \ sides \ of \ the \ equation\\\\2 + 5t^2 = \frac{dv}{dt} \\\\\int\limits^3_0 {(2 + 5t^2)} \, dt = dv\\\\v = [2t + \frac{5t^3}{3} ]^3_0\\\\v = 2(3) + \frac{5(3)^3}{3} \\\\v = 6 + 5(3)^2\\\\v = 6 + 45\\\\v = 51 \ m/s

Therefore, the instantaneous velocity is 51 m/s

7 0
3 years ago
What is one similarity and one difference between photons of visible light and UV radiation?
gavmur [86]

Answer:

They have the same speed

They have different frequencies

Explanation:

One similarity between photons of visible light and UV radiation is that they both travel at the same speed of light.

One difference between photons of visible light and UV radiation is that they have different frequencies.

5 0
2 years ago
Luyando wants to have a bit of fun with her wagon. She puts her 12 baby sister, Waluse, on the wagon and pulls it across the flo
max2010maxim [7]

Answer:

work energy equation

w.d(external)= \delta \: k.e+ \:  \:  \ \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: w.d(ressesive)

Explanation:

first of all we have to find reaction force to find fr

fr =   \mu \: mg \\ mg = reaction \: force(r) \\ f = ma \\ r + 40 \sin(22)  - 150 = 0 \\ r = 150 - 40 \sin(22)

then let's find friction

fr =  \mu \: r \\ 0.2 \times (150 - 40 \sin(22) )

then let's apply work energy principle...its on the 2nd picture

<h2>v = 2.3ms^-1</h2>

6 0
2 years ago
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