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kobusy [5.1K]
4 years ago
11

A metal wire is in thermal contact with two heat reservoirs at both of its ends. Reservoir 1 is at a temperature of 563 K, and r

eservoir 2 is at a temperature of 354 K. Compute the total change in entropy arising from the conduction of 1760 J of heat through the wire. Please give your answer in units of J/K.
Physics
1 answer:
Schach [20]4 years ago
8 0

Answer:

1.85 J/K

Explanation:

The computation of total change in entropy is shown below:-

Change in Entropy = Sum Q ÷ T

= \frac{-heat\ entering\ the\ reservoir}{Reservoir\ 1\ Temperature} + \frac{Conduction\ of\ heat}{Reservoir\ 2\ Temperature}

= \frac{-1760}{563} + \frac{1760}{354}

= -3.12 + 4.97

= 1.85 J/K

Therefore for computing the total change in entropy we simply applied the above formula.

As we can see that there is heat entering the reservoir so it will be negative while cold reservoir will be positive else the process would be impossible.

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Compute your average velocity in the following two cases: (a) You walk 50.2 m at a speed of 2.21 m/s and then run 50.2 m at a sp
Readme [11.4K]

Answer:

a) 2.87 m/s

b) 3.23 m/s

Explanation:

The avergare velocity can be found dividing the length traveled d by the total time t.

a)

For the first part we easily know the total traveled length which is:

d = 50.2 m + 50.2 m = 100.4 m

The time can be found dividing the distance by the velocity:

t1 = 50.2 m / 2.21 m/s = 22.7149 s

t2 = 50.2 m / 4.11 m/s = 12.2141 s

t = t1 +t2 = 34.9290 s

Therefore, the average velocity is:

v = d/t =2.87 m/s

b)

Here we can easily know the total time:

t = 1 min + 1.16 min = 129.6 s

Now the distance wil be found multiplying each velocity by the time it has travelled:

d1 = 2.21 m/s * 60 s = 132.6 m

d2 = 4.11 m/s *(1.16 * 60 s) = 286.056 m

d = 418.656 m

Therefore, the average velocity is:

v = d/t =3.23 m/s

5 0
3 years ago
Galois drove 60.0 kilometers due west in 5.00 hours and then drove 43.0 kilometers due north in 3.00 hours.
IceJOKER [234]

Answer:

Explanation:

See the attachment for the details.  A right triangle is formed to find the hypotenuse of the two legs consisting of the actual driving distances and times.  The hypotenuse gives the vector information for the displacement at the end of 8 hours of driving.  

The individual driving times and distances are summed to provide:

(<u>a) How far did he travel?</u>

103 km

<u>(b) What was his average speed?</u>

12.88 km/h

<u>(c) What was his displacement?</u>

73.82 km

<u>(d) What was his average velocity?</u>

9.228 km/h

8 0
3 years ago
About 2% of our solar nebula consisted of elements besides hydrogen and helium. However, the very first generation of star syste
Mariulka [41]

Answer:

Answer

Explanation:

The very first generation of star systems in the universe probably consisted only of hydrogen and helium. This means that,

There were no comets or asteroids in these first-generation star systems. As the comets and asteroids were the only soruce of elements other than Hydrogen and Heliums ( As starts mainly consists of helium and hydrogen).

3 0
3 years ago
A source charge of 3 µC generates an electric field of 2.86 × 105 N/C at the location of a test charge. Using k = 8.99 × 109N.m^
Nataliya [291]
Variables:

Source charge, Q = 3 micro C = 3 * 10^ - 6 C

E = electric field = 2.86 * 10 ^5 N/C

K = 8.99 * 10^9 N * m^2 / C

d = distance = ?

Formula:

E = K * Q / (d^2) => d^2 = K * Q / E

=> d^2 = 8.99 * 10^9 N * m^2 / C * 3 * 10^ -6 C / (2.86 * 10^ 5 N/C)

d^2 = 9.43 * 10 ^ -2  m^2

=> d = 3.07 * 10^-1 m

Answer: 0.307 m

Note: it is a long distance due to the Electric field is very low
7 0
3 years ago
Read 2 more answers
Chewy travels an average of 22 mph, how many hours does it take him to cover a 110 mike course?
anzhelika [568]
That would be 110/22, which is 5 hours
5 0
3 years ago
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