Answer:
5.38 m/s^2
Explanation:
NET force causing the object to accelerate = 50 -10 = 40 N
Mass of the object = 73 N / 9.81 m/s^2 = 7.44 kg
F = ma
40 = 7.44 * a a = 5.38 m/s^2
Answer:
a) 141.6m
b) 8.4m/s
Explanation:
a) to find the total displacement you use the following formula for each trajectory. Next you sum the results:
![x_1=v_1t_1=(12m/s)(9s)=108m\\\\x_2=v_2t_2=(4.8m/s)(7s)=33.6m\\\\x_T=x_1+x_2=108m+33.6m=141.6m](https://tex.z-dn.net/?f=x_1%3Dv_1t_1%3D%2812m%2Fs%29%289s%29%3D108m%5C%5C%5C%5Cx_2%3Dv_2t_2%3D%284.8m%2Fs%29%287s%29%3D33.6m%5C%5C%5C%5Cx_T%3Dx_1%2Bx_2%3D108m%2B33.6m%3D141.6m)
hence, the total distance is 141.6m
b) the mean velocity of the total trajectory is given by:
![v_m=\frac{v_1+v_2}{2}=\frac{12m/s+4.8m/s}{2}=8.4\frac{m}{s}](https://tex.z-dn.net/?f=v_m%3D%5Cfrac%7Bv_1%2Bv_2%7D%7B2%7D%3D%5Cfrac%7B12m%2Fs%2B4.8m%2Fs%7D%7B2%7D%3D8.4%5Cfrac%7Bm%7D%7Bs%7D)
hence, the mean velocity is 8.4 m/s
It would be d all of the above
<h2>Hello!</h2>
The answer is: 19.59 m
<h2>Why?</h2>
Since there is no information about the launch type, we can assume that the ball is thrown vertically upward.
When the ball reaches the maximum height, just at that moment, the velocity turns to 0, and after that moment, the ball starts falling, so:
We will use the following formula:
![Vf^2=Vi^2+2*g*s](https://tex.z-dn.net/?f=Vf%5E2%3DVi%5E2%2B2%2Ag%2As)
Where:
Vf= Final velocity = 0
Vi= Initial velocity = ![\frac{19.6m}{s}](https://tex.z-dn.net/?f=%5Cfrac%7B19.6m%7D%7Bs%7D)
g = Gravity Acceleration = ![\frac{9.81m}{s^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B9.81m%7D%7Bs%5E%7B2%7D%20%7D)
s = Traveled distance
![0=19.6^2+2*-9.81*s\\s=\frac{19.6^2}{2*9.81}=\frac{384.16}{19.62}=19.59m](https://tex.z-dn.net/?f=0%3D19.6%5E2%2B2%2A-9.81%2As%5C%5Cs%3D%5Cfrac%7B19.6%5E2%7D%7B2%2A9.81%7D%3D%5Cfrac%7B384.16%7D%7B19.62%7D%3D19.59m)
Have a nice day!