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3 years ago

The diagram shows a stone tied to a string in circular

Physics

1 answer:

yKpoI14uk [10]3 years ago

5 0

Answer:

Newton's First Law of motion states that an object will continue to move in a straight line or remain at rest unless a force acts on it

The stone is able to move in circular motion because a (centripetal) force acts through the string on it, which maintains the circular motion, by turning the stone to the circular path as the stone moves with momentary velocity along a straight line which is (therefore) tangential to the circle

Therefore, at the point the spring breaks, the centripetal force is no longer acting on the stone to change its path and the motion of the continues on the tangent to the initial circular motion path at that point

Explanation:

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People began to study classical thought wing the Renaissance to

MrRissso [65]

Answer:

Explanation:

to better themselves and to be good educated people

3 0

3 years ago

A cube, whose edges are aligned with the , and axes, has a side length . The field is immersed in an electric field aligned with

Ivenika [448]

Complete Question

Complete Question is attached below

Answer:

$q=1.558*10^{-9}c$

Explanation:

From the question we are told that:

Side length s=1.13m

Left field strength $E_l=784.75N/m$

Right field strength $E_r=776.38 N/m$

Front field strength $E_f=725.5 N/m$

Back field strength $E_b=749.54 N/m$

Top field strength $E_t=944.95 N/m$

Bottom field strength $E_{bo}=1082.58 N/m$

Generally, the equation for Charge flux is mathematically given by

$\phi=EAcos\theta$

Where

Theta for Right,Left,Front and Back are at an angle 90

$cos 90=0$

Therefore

$\phi =0$ with respect to Right,Left,Front and Back

Generally, the equation for Charge Flux is mathematically also given by

$\phi=\frac{q}{e_o}$

Where

$Area =L*B\\\\A=1.13*1.13\\\\A=1.2769m^2$

Therefore

$Q_{net}=E_{bo}Acos\theta_{bo} +E_tAcos\theta_t$

$Q_{net}=1082.85*1.2769*cos0=944.95*1.2769cos (180)$

$Q_{net}=176N/C m^2$

Giving

$q=\phi*e_0$

$q=176N/C m^2*1.558*10^{-12}c$

$q=1.558*10^{-9}c$

4 0

3 years ago

(01.06 LC)

Marta_Voda [28]

Answer:

Equilibrium is reached when demand equals supply.

Explanation:

Demand is the amount that consumers want and can buy of a certain product or service in a specific period of time and at a certain price. On the other hand, the supply is the amount that producers want and can sell of a certain product or service in a specific period of time and at a certain price.

In market equilibrium, the quantity demanded of the product or service equals the quantity supplied, so the price also equals. In other words, when market equilibrium is reached, demand and supply are the same, with their corresponding equilibrium price and quantity.

Two situations can occur:

When the quantity demanded is greater than the quantity supplied, the market is in a situation of excess demand.

On the other hand, it may happen that the price at which the products are being offered is greater than the equilibrium price and the quantity supplied is greater than the quantity demanded. Then there is an excess supply.

Equilibrium is reached when demand equals supply.

4 0

4 years ago

Two resistors ( 3 ohms & 6 ohms) in a Parallel circuit with a power supply = 12 volts. The current through resistor 3 ohms i

balu736 [363]

Answer:

4 A

Explanation:

5 0

3 years ago

To stop a car, first you require a certain reaction time to begin braking; then the car slows under the constant braking deceler

kirza4 [7]

Answer:

a.) 2.66 seconds for 79.2 km/h and 1.82 seconds for 47.8 km/h

b.)-4.13 m/s2 for 79.2 km/h and -3.63 m/s2 for 47.8 km/h

Explanation:

Now for (a)

time = velocity/distance

for velocity = 79.2 km/h and distance 0.0586 km

t = (0.0586/79.2)*3600

t = 2.66 seconds (Please note that multiplication with 3600 is to convert hours into seconds)

for velocity 47.8 km/h and distance 0.0242 km

t = (0.0242/47.8)*3600

t = 1.82 seconds

Now for (b)

2as = vf2-vi2

so,

2a(58.6) = -(79.2*1000/3600)^2 (Please note that multiplication and division with 1000 and 3600 respectively is to convert speed unit from km/h to m/s)

a = -4.13 m/s2 for 58.6 m

and

2a(24.2) = -(47.8*1000/3600)^2

a = -3.63 m/s2 for 24.2 m.

Please note that "-" sign express the deceleration.

5 0

3 years ago