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CaHeK987 [17]
3 years ago
6

You exert a force of 25 newtons while you move a rock 15 meters. How much work did you perform?

Physics
1 answer:
leonid [27]3 years ago
4 0
Work Done = Force x Distance Moved
Work Done = 25 x 15 = 375 Joules
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3 years ago
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If it requires 2.0 J of work to stretch a particular spring by 2.0 cm from its equilibrium length, how much more work will be re
valina [46]

Answer:

16 J

Explanation:

It is given that,

Work done, W = 2 J

A spring is stretched by 2.0 cm from its equilibrium length

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Let k is the spring constant of the spring. When W = 2J, and x = 2 cm, then energy required to stretch the spring is :

U=\dfrac{1}{2}kx^2\\\\k=\dfrac{2U}{x^2}\\\\k=\dfrac{2(2)}{(0.02)^2}\\\\k=10000\ N/m

The energy required to stretch the spring from 2 cm to additional 4 cm i.e. 2+4= 6 cm.

W=\dfrac{1}{2}k(x_2^2-x_1^2)\\\\=\dfrac{1}{2}\times 10000\times ((0.06)^2-(0.02)^2)\\\\W=16\ J

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7 0
3 years ago
What equation describes conservation of charge?
Phantasy [73]

Answer:

The equation which describes conservation of charge is Q_{initial} - Q_{final } = 0

Explanation:

The law of conservation charge states that for an isolated system that sum of initial charges is equal to sum of final charges, that is the total charge is conserved.

let the sum of initial charges = Q_{initial}

let the sum of the final charges = Q_{final}

Q_{initial } = Q_{final}\\\\Q_{initial } - Q_{final} = 0

Therefore, the equation which describes conservation of charge is Q_{initial} - Q_{final } = 0

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We know, velocity = Displacement/Time

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