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Gnesinka [82]
1 year ago
12

Read this article discussing the amount of time that people of various ages and education levels report spending on different te

chnologies. Ask at least 12 of your adult friends and family members the same survey question. (The more people you ask, the better.) How do your survey results compare with the results in the article? What are some possible reasons your results might be different? When comparing the results, be sure to take into account the margin of error for the survey discussed in the article
Physics
1 answer:
iVinArrow [24]1 year ago
7 0

The article is not found here but surveys are important because they are representative samples of a population.

<h3>What is a survey?</h3>

A survey is a useful tool based on population samples, which is used to make statistical analyses in a given investigation.

Differences in surveys are generally due to small sample sizes, which may lead to errors in the analysis of data.

In conclusion, the article is not found here but surveys are important because they are representative samples of a population.

Learn more about surveys here:

brainly.com/question/13624055

#SPJ1

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An proton-antiproton pair is produced by a 2.20 × 10 3 MeV photon. What is the kinetic energy of the antiproton if the kinetic e
timama [110]

Answer:

K = 80.75 MeV    

Explanation:

To calculate the kinetic energy of the antiproton we need to use conservation of energy:

E_{ph} = E_{p} + E_{ap} = E_{0p} + K_{p} + E_{0ap} + K_{ap} = m_{0p}c^{2} + K_{p} + m_{0ap}c^{2} + K_{ap}

<em>where E_{ph}: is the photon energy, E_{0p} and E_{0ap}: are the rest energies of the proton and the antiproton, respectively, equals to m₀c², K_{p} and K_{ap}: are the kinetic energies of the proton and the antiproton, respectively, c: speed of light, and m₀: rest mass.</em>        

Therefore the kinetic energy of the antiproton is:    

K_{ap} = E_{ph} - m_{0p}c^{2} - K_{p} - m_{0ap}c^{2}

<u>The proton mass is equal to the antiproton mass, so</u>:

K_{ap} = E_{ph} - 2m_{0p}c^{2} - K_{p}  

K_{ap} = 2.20 \cdot 10^{3}MeV - 2(1.67 \cdot 10^{-27}kg)(3\cdot 10^{8} \frac {m}{s})^{2} - 242.85MeV

K_{ap} = 2.20 \cdot 10^{3}MeV - 2(1.67 \cdot 10^{-27}kg)(3\cdot 10^{8} \frac {m}{s})^{2}(\frac{1eV}{1.602 \cdot 10^{-19}J})(\frac{1 MeV}{10^{6}eV}) - 242.85MeV

K_{ap} = 80.75 MeV              

Hence, the kinetic energy of the antiproton is 80.75 MeV.

I hope it helps you!

3 0
3 years ago
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