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NemiM [27]
3 years ago
8

3. Categorize each statement as true or false. True False as the fringe order increase for a diffraction grating the fringe brig

htness decreases
Physics
1 answer:
o-na [289]3 years ago
3 0

Answer:

True

Explanation:

According to the given situation, the statement is correct as it is secondary maxima of declining strength in the diffraction pattern.

Therefore, the fringe brightness decreases, the fringe order increase for a diffraction grating. So, the right answer is true.

So from the above explanation, the given statement is true

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Margaret, a researcher, desires to conduct a field experiment to determine the effects of a shopping mall's ambience on consumer
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Answer:

Extraneous

Explanation:

Extraneous variables are any variables that you are not intentionally studying in your experiment or test

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3 years ago
If something is a good conductor, what type of insulator is it?
nlexa [21]

4. a poor insulator

If rest other things are kept constant or unchanged then a good conductor can be termed as a poor insulator.

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What type of motion occurs when an object spins around an axis without altering its linear position?
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<h2><em>C. translational motion</em></h2><h2><em>HOPE IT HELPS !!!!!</em></h2>
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What wavelength would a ripple in water have if the frequency is 1.8 Hz and a
Yuki888 [10]

Explanation:

825m/s / 1.8Hz = 458.33m

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2 years ago
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An object moving in circular motion has a mass of 15 kg and a centripetal acceleration of 10 m/s2. What is the centripetal force
sweet-ann [11.9K]

Answer:

1) A

2) C

3) B

4) A

5) Incomplete information(picture missing)

6) Incomplete information(picture missing)

7) Incomplete information(picture missing)

8) A

9) C

10) C

Explanation:

1) m = 15kg, a = 10ms^{-2}, F = ma = 15*10 = 150N

2) m = 3kg, v = 4ms^{-1}, r = 4m, F = \frac{mv^{2} }{r}

\frac{3*4^{2} }{4} = 12N

3) a = 10ms^{-2}, r = 10m, v=?

F = \frac{mv^{2} }{r} and F = ma

equating the two equations and cancelling a, we have:

\frac{v^{2} }{r} = a

making v the subject of formula, we have:

v = \sqrt{ar}

= \sqrt{100}

= 10ms^{-1}

4) r = 10m, v = 5ms^{-1}, a = ?

F = \frac{mv^{2} }{r}

F = ma

equating the above equations and making a subject of formula, we get:

a = \frac{v^{2} }{r}

a = 25/10 = 2.5ms^{-2}

5) I can't find the picture associated with this question

6) I can't find the picture associated with this question

7) I can't find the picture associated with this question

8) F = \frac{mv^{2} }{r}

assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:

F = v^{2}

Now, if v is tripled

F = (3v)^{2}

F = 9v^{2}

We can see that the force will be 9X greater than it was.

9) F = \frac{mv^{2} }{r}

assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:

F = v^{2}

Now, if v is doubled

F = (2v)^{2}

F = 4v^{2}

We can see that the force will be 4X greater than it was.

10) F = \frac{mv^{2} }{r}

assuming m and v is unity, that is the values are 1 respectively

F = 1/r

if r is doubled,

F = 1/2 * 1/r

We can see that the force is 1/2 as big as it was

7 0
3 years ago
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