Answer:
option (d) and (f) is correct.
The solution of given quadratic equation is 3 and -9.
Step-by-step explanation:
Given quadratic equation 
We have to solve the given quadratic equation using quadratic formula.
Consider
, we can rewrite it as 
For the general quadratic equation
the quadratic formula is given as 
Here a = 1 , b= 6 and c = -27
Substitute, we get,

Solving further , we get,


We know
, we get,

and 
Solving we get,
and 
and 
Thus, the solution of given quadratic equation is 3 and -9.
Thus, option (d) and (f) is correct.