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Airida [17]
4 years ago
10

Shelly bought 5 pounds of bananas for $1.10. How much were the bananas per pound?

Mathematics
2 answers:
Dominik [7]4 years ago
8 0

Answer:

$0.22

Stage 1: Divide.

$1.10 ÷ 5 = $0.22.

Your answer would be $0.22 per pound. Hope it helps!

Marta_Voda [28]4 years ago
3 0
The answer is 22 cents
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A sample of size 100 is selected from a population with p = .40.
zhuklara [117]

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(a) 0.40

(b) 0.049

(c) \bar p\sim N(0.40,0.049^{2})

(d) Explained below

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 E(\bar p)=p

The standard deviation of this sampling distribution of sample proportion is:

 SE(\bar p)=\sqrt{\frac{p(1-p)}{n}}

Given:

n = 100

p = 0.40

As <em>n</em> = 100 > 30 the Central limit theorem is applicable.

(a)

Compute the expected value of \bar p as follows:

E(\bar p)=p=0.40

The expected value of \bar p is 0.40.

(b)

Compute the standard error of \bar p as follows:

SE(\bar p)=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.40(1-0.40)}{100}}=0.049

The standard error of \bar p is 0.049.

(c)

The sampling distribution of \bar p is:

\bar p\sim N(0.40,0.049^{2})

(d)

The sampling distribution of p show that as the sample size is increasing the distribution is approximated by the normal distribution.

3 0
4 years ago
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