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Nina [5.8K]
3 years ago
5

4. A bacterial cell is prokaryotic, while the protist, Euglena, is eukaryotic. Which structure is present

Biology
2 answers:
Korolek [52]3 years ago
6 0
Plasma membrane is the answer
dmitriy555 [2]3 years ago
3 0

Answer:

There are a couple different possible answers, since there are multiple different structures that are present in both types of cells. So you have to make the choice of what to put.

The structures that prokaryotic and eukaryotic cells have in common are: plasma membrane, ribosomes,  and cytoplasm

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Describe some of the ways in which real-world pateontology is different from how it is presented in movies
garik1379 [7]

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Paleontology in the real world isn't as careless and usually in movies they mis-label things. Paleontology isn't as simple as it seems and in many movies they portray little effort or processing and handling of the fossils. It requires much attention and you have to take care of the bones. Jurassic Park is a great example of fake paleontology and comparing it to real paleontology can surprise you.

Explanation:

7 0
3 years ago
A geologic unit is a(n)
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4 0
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When atp breaks down to adp, potential energy stored in bonds is released. this energy stored in bonds is __________ energy?
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3 years ago
× the process of dna replication occurs just before ______________
Sliva [168]
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4 0
4 years ago
An amoeba reproduces by splitting itself into two amoebas. This means that the original amoeba dies and its two offspring live o
Naddika [18.5K]

Answer:

If one amoeba dies then two amoeba get born:

at different stages of the generations of the amoeba it changes accordingly and the died amoeba numbers are also change in the given manner :

          stages    dies                          born

          I               1                                2

          II              2^{1}           4 = 2^{2}

          III              2^{2}          8 = 2^{3}

At  n^{th} =  2^{n}    2^{n+1}

By the geometric series formula:

 1+a^{1}+ a^{2}+ a^{3}...+ a^{n}=\frac{a^{n+1} }{a^-1} }

so,  1+2^{1}+ 2^{2}+ 2^{3}...+ 2^{n}=\frac{2^{n+1} }{2^-1} }

Thus, total amoeba died = 2^{n+1}-1

        total amoeba died+1 = 2^{n+1} (born).... hence prooved

5 0
3 years ago
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