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Licemer1 [7]
3 years ago
11

Cuanto es 7 gal 1 qt - menos 2 gal 3 qts

Mathematics
1 answer:
Lana71 [14]3 years ago
8 0
La respuesta es que quedan 4 gal y 8 qts
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write an equation in slope intercept form for the line that passes through the points (3,2) and(-9,6)
netineya [11]

Answer:

y = - \frac{1}{3} x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (3, 2) and (x₂, y₂ ) = (- 9, 6)

m = \frac{6-2}{-9-3} = \frac{4}{-12} = - \frac{1}{3}, hence

y = - \frac{1}{3} x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (- 9, 6), then

6 = 3 + c ⇒ c = 6 - 3 = 3

y = - \frac{1}{3} x + 3 ← in slope- intercept form

4 0
3 years ago
What is the value of x in this triangle
Rom4ik [11]
63+74+x=180
180-63-74=43
x=43
3 0
3 years ago
ALGEBRA 1:
inna [77]
Distribution method
(2x+6)(2x-6)
=4x^2-12x+12x-36
=4x^2-36
7 0
3 years ago
Read 2 more answers
Put these numbers lest to greatest<br><br> 1.4 ,0.5 ,0.75 ,0.25​
elena55 [62]

Answer:

0.25,0.5,0.75,1.4

Step-by-step explanation:

smaller decimals go first

7 0
3 years ago
2. The Hereford Cattle Society says that the mean weight of a one-year-old Hereford bull is 1135 pounds, with a standard deviati
Andrews [41]

Answer:

16.35% probability their combined weight exceeds 46000 pounds.

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 1135, \sigma = 97, n = 40, s = \frac{97}{\sqrt{40}} = 15.34

Find the probability their combined weight exceeds 46000 pounds.

This is 1 subtracted by the pvalue of Z when X = \frac{46400}{40} = 1150. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1150 - 1135}{15.34}

Z = 0.98

Z = 0.98 has a pvalue of 0.8365

1 - 0.8365 = 0.1635

16.35% probability their combined weight exceeds 46000 pounds.

5 0
3 years ago
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