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3 years ago

Identify the type of conic; then the equation to the standard form for that conic: X^2-2x-16y+33=0

Mathematics

1 answer:

ZanzabumX [31]3 years ago

4 0

That will idk but thanks anyways

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I need help pls !!!!!!

Rama09 [41]

(k-7) would be the equation

6 0

3 years ago

What is the slope of the line shown below?

Anton [14]

Answer:

Slope = 3

Step-by-step explanation:

2 - 8 = -6

2 - 4 = -2

Slope = 3

8 0

3 years ago

I dont understand this question, i did the factor of 36x^2 - 49 but I dont understand the second part

Nadya [2.5K]

Answer:

a = 6

b = 7

Step-by-step explanation:

Since both 36 and 49 are perfect squares, you can find their square roots which are 6 and 7.

To check to see if it is correct, replace the a with 6 and replace the b with 7, then evaluate the exponents.

8 0

2 years ago

HELP!!! ASAP!!!

ololo11 [35]

1+1+2+2+3+3+4+4+5+5 is your answer. If it's wrong I'm sorry

7 0

2 years ago

Consider the line y = 7x-9.

KatRina [158]

$y = \frac{-1}{7}x -\frac{8}{7}$ is the equation of the line that is perpendicular to this line and passes through the point (6, -2)

y = 7x - 44 equation of the line that is parallel to this line and passes through the point (6, -2)

Solution:

Given that line is:

y = 7x - 9

The equation of line in slope intercept form is given as:

y = mx + b ------ eqn 1

Where, "m" is the slope of line and "b" is the y intercept

On comparing eqn 1 with y = 7x - 9 we get,

m = 7

<h3>Find the equation of the line that is perpendicular to this line and passes through the point (6, -2)</h3>

We know that,

Product of slope of a line and slope of line perpendicular to given is always -1

Therefore,

$7 \times \text{ slope of line perpendicular to it } = -1\\\\\text{ slope of line perpendicular to it } = \frac{-1}{7}$

Now find the equation of line:

$\text{ Substitute } m = \frac{-1}{7} \text{ and } (x, y) = (6, -2) \text{ in eqn 1}$

$-2 = \frac{-1}{7} \times 6 + b\\\\-2 = \frac{-6}{7} + b\\\\b = -2+\frac{6}{7}\\\\b = \frac{-14+6}{7}\\\\b = \frac{-8}{7}$

$\text{Substitute } m = \frac{-1}{7} \text{ and } b = \frac{-8}{7} \text{ in eqn 1}\\\\y = \frac{-1}{7}x -\frac{8}{7}$

Thus the equation of line perpendicular to given line is found

<h3>Find the equation of the line that is parallel to this line and passes through the point (6, -2)</h3>

Slopes of parallel lines are equal

Therefore, m = 7

Substitute m = 7 and (x, y) = (6, -2) in eqn 1

-2 = 7(6) + b

-2 = 42 + b

b = -44

Substitute m = 7 and b = -44 in eqn 1

y = 7x - 44

Thus equation of line parallel to given line is found

8 0

3 years ago