Answer:
an isosceles right triangle
Step-by-step explanation:
The square of the length of a side can be found from the distance formula:
d^2 = (x2-x1)^2 +(y2-y1)^2
The square of the length of WX is ...
WX^2 = (-3-(-10))^2 +(-1-4)^2 = 49+25 = 74
The square of the length of XY is ...
XY^2 = (-5-(-3))^2 +(11-(-1))^2 = 4 +144 = 148
The square of the length of YW is ...
YW^2 = (-10-(-5))^2 +(4 -11)^2 = 25 +49 = 74
The sum of the squares of the short sides is equal to the square of the long side, so this is a right triangle. The squares of the short sides are equal, so this is an isosceles right triangle.
The first thing you should do in that case is to graph both lines.
Once graphed you must see which region of the Cartesian plane they meet their respective inequalities.
The solution of the inequation system is the shaded region shown.
The point sought is
P = (5, -2)
answer<span>
(5, –2)</span>
Answer:
say no more , link it down below
4 to he power of 1/2 is 2
I think thats because its 1/2 of 2
Sorry if I'm wrong
Hope this helps
Just took the test. A is the right answer.