What is the vaule of x

Mathematics

1 answer:

Leno4ka [110]3 years ago

4 0

Answer:

one because x represent 1

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7,000 is 10 times as much as

Llana [10]

I think the answer is 700 as 700*10=7,000.

3 0

3 years ago

The sum of two numbers is 44. One number is 2 more than twice the other. Write a system of equations that defines this situation

hram777 [196]

System: x + y = 44; x = 2y + 2

Solve with substitution: x = 30; y = 14

x + y = 44
x = 2y + 2

Substitute 2y + 2 for x

2y + 2 + y = 44

3y + 2 = 44

Subtract 2 on both sides.

3y = 42

y = 14

Now substitute back in.

x + 14 = 44

Subtract 14 on both sides.

x = 30

8 0

3 years ago

Read 2 more answers

Use the difference of squares identity to write this polynomial expression in factored form: 9x2 − 49.

qwelly [4]

9x^2-49
It equals:
(3x+7)(3x−7)
Hope this helps!

7 0

3 years ago

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Find the inverse of ????−7 −2

Masja [62]

Answer:

$A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

Step-by-step explanation:

$A=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}$

$det\ A=-7\times 1-(-2)\times 4\\\Rightarrow det\ A=1$

$A^{-1}=\frac{1}{det\ A}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\frac{1}{1}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

$\therefore A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

$A.A^{-1}=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}\times \begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}\left(-7\right)\cdot \:1+\left(-2\right)\left(-4\right)&\left(-7\right)\cdot \:2+\left(-2\right)\left(-7\right)\\ 4\cdot \:1+1\cdot \left(-4\right)&4\cdot \:2+1\cdot \left(-7\right)\end{pmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}1&0\\ 0&1\end{pmatrix}$

Hence, confirmed

6 0

3 years ago

Someone please help and and make sure the answer is right :)

marishachu [46]

6, it’s equal to 47, so 7(6)+5=47

7 0

3 years ago