The sum of two numbers is 44. One number is 2 more than twice the other. Write a system of equations that defines this situation
and solve using any method.
2 answers:
System: x + y = 44; x = 2y + 2
Solve with substitution: x = 30; y = 14
x + y = 44
x = 2y + 2
Substitute 2y + 2 for x
2y + 2 + y = 44
3y + 2 = 44
Subtract 2 on both sides.
3y = 42
y = 14
Now substitute back in.
x + 14 = 44
Subtract 14 on both sides.
x = 30
Answer:
20 + 24 = 44
Hoped this helped :)
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