Question

The sum of two numbers is 44. One number is 2 more than twice the other. Write a system of equations that defines this situation and solve using any method.

Answer 1

System: x + y = 44; x = 2y + 2

Solve with substitution: x = 30; y = 14



x + y = 44
x = 2y + 2

Substitute 2y + 2 for x

2y + 2 + y = 44

3y + 2 = 44

Subtract 2 on both sides.

3y = 42

y = 14

Now substitute back in.

x + 14 = 44

Subtract 14 on both sides.

x = 30

Answer 2

Answer:

20 + 24 = 44

Hoped this helped :)