Greetings from Brasil...
Let's apply the given formula:
A = (1/2)·B·H
The base of this polygon (in this case, the triangle) is B
B = X² - 2X + 6
The height of this polygon is H and is H
H = X + 4
Applying these values (B and H) in the given formula.....
A = (1/2)·B·H
A = (1/2)·(X² - 2X + 6)·(X + 4)
A = (1/2)·(X³ + 2X² - 2X + 24)
A = (X³/2) + X² - X + 12
OR
A = (X³ + 2X² - 2X + 24)/2
Answer:
the probability that the first to arrive has to wait longer than 10 mins is 35/36.
Step-by-step explanation:
First you need to denote by X and Y the time past 12 noon that the man and woman arrive.
Then you have to compute P(X+10<Y)+P(Y+10<X), which by symmetry equals 2P(X+10<Y).
So basically you have to compute P(X+10<Y).
check the attachment for the rest of the step by step.
Answer should be 25/72
But since we want 2× of the above probability 2× 25/72 = 25/36 final answer.
Answer:
I think there is an error in the question because
(f-g) = -4
(f-g) (7) = NO SOLUTION
Step-by-step explanation: