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lapo4ka [179]
2 years ago
12

Please help. I don’t understand how to do this

Mathematics
2 answers:
yKpoI14uk [10]2 years ago
5 0

Answer:

First find hypotenuses

Step-by-step explanation:

First you must find h by using formula

A^2+b^2=c^2 when you find this you already given base and put the c you find is h and b is given in the formula you will get area

Rasek [7]2 years ago
4 0

Greetings from Brasil...

Let's apply the given formula:

A = (1/2)·B·H

The base of this polygon (in this case, the triangle) is B

B = X² - 2X + 6

The height of this polygon is H and is H

H = X + 4

Applying these values (B and H) in the given formula.....

A = (1/2)·B·H

A = (1/2)·(X² - 2X + 6)·(X + 4)

A = (1/2)·(X³ + 2X² - 2X + 24)

A = (X³/2) + X² - X + 12

OR

A = (X³ + 2X² - 2X + 24)/2

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Step-by-step explanation:

Complementary angles add up to 90°

Supplementary angles add up to 180°

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What is the length of DE?
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Answer:

Step-by-step explanation:

Yes

Theorem 8.3: If two angles are complementary to the same angle, then these two angles are congruent.

∠A and ∠B are complementary, and ∠C and ∠B are complementary.

Given: ∠A and ∠B are complementary, and ∠C and ∠B are complementary.

Prove: ∠A ~= ∠C.

 Statements Reasons

1. ∠A and ∠B are complementary, and ∠C and ∠B are complementary. Given

2. m∠A + m∠B = 90º , m∠C + m∠B = 90º Definition of complementary

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5. ∠A ~= ∠C Definition of ~=

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