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Dima020 [189]
3 years ago
13

Consider the graph of f(x) on the interval [−6,2] shown. The local minimum of f(x) is at the point _[blank ]_.

Mathematics
1 answer:
Anna71 [15]3 years ago
6 0

Answer:

598,256,987,532,123

Step-by-step explanation:

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anygoal [31]
Find numbers that multiply to 28 and add them to see if they add to 8
28=
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that's it'
no 2 numbers
we must use quadratic formula

x+y=8
xy=28

x+y=8
subtract x fromb oths ides
y=8-x
subsitute
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distribute
8x-x^2=28
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subtract 8x
x^2-8x+28=0

if you have
ax^2+bx+c=0 then x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}
so if we have
1x^2-8+28=0 then
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x=\frac{-(-8)+/- \sqrt{(-8)^{2}-4(1)(28)} }{2(1)}
x=\frac{8+/- \sqrt{-48} }{2}
x=\frac{8+/- 4 \sqrt{-3} }{2}
x=4+/- 2 \sqrt{-3}
x=4+/- 2i \sqrt{3}
there are no real numbers that satisfy this
5 0
4 years ago
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