Find numbers that multiply to 28 and add them to see if they add to 8
28=
1 and 28=29 not 8
2 and 14=16 not 8
4 and 7=11 not 8
that's it'
no 2 numbers
we must use quadratic formula
x+y=8
xy=28
x+y=8
subtract x fromb oths ides
y=8-x
subsitute
x(8-x)=28
distribute
8x-x^2=28
add x^2 to both sides
8x=28+x^2
subtract 8x
x^2-8x+28=0
if you have
ax^2+bx+c=0 then x=

so if we have
1x^2-8+28=0 then
a=1
b=-8
c=28
x=

x=

x=

x=

x=

there are no real numbers that satisfy this
The reduced form of
74
360
is
37
180
Answer: He would earn $14
Step-by-step explanation: Since Sam had 11 games but only 9 of them were working just take 11 - 9 which = 2 then take 7 x 2 to get $14
Hope this helps
A question such as this one is a little tricky since the people seated are not in a straight line.
For a circular table seating question, (n-1)! formula is used. Without restrictions 5! people can be seated.
You might be wondering why it is not 6!, this is because the first person will the the 6 person so you are accounting for the same person twice.
Hope I helped :)