Answer:
s = 22.5 m
Step-by-step explanation:
the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.
v (t) = 25 - 5 t
at t = 0 , v = 20 m/s
Let the distance is s.

Let at t = t, the v = 20
So,
20 = 25 - 5 t
t = 1 s
So, s = 25 x 1 - 2.5 x 1 = 22.5 m
Answer:
In this question, we can use the Pythagorean theorem to solve for x.
11^2 + x^2 =24^2
x^2 = 24^2 -11^2
x is about 21.3
Let me know if this helps!
I'm assuming you want an equation with a slope of -5 that also passes through the point (1, -7).
An equation that fits this is

Hope this helps!
=(9(1/3))^2+2+4/7
=(3^2)+2+4/7
=(9)+2+4/7
=11+4/7
=81/7
X2+5x-150= <span><span> x = 10 </span><span> x = -15
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