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3 years ago

Solve for b1176327160

Mathematics

2 answers:

Black_prince [1.1K]3 years ago

6 0

Answer:

B) 27

Step-by-step explanation:

Because 153 and b are a linear pair, their angle measures must add up to 180 degrees. Therefore:

153+b=180

b=180-153

b=27

Hope this helps!

Alisiya [41]3 years ago

3 0

Answer:

Step-by-step explanation:

180-153=b

b=27

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two mountain bikers leave from the same parking lot and head in opposite directions on two different trails. the first rider goe

sveta [45]

Applying the required rule or theorem, it can be concluded that the second biker is farther from the parking lot. The distance of the bikers to the parking lot are:

i. First biker = 17.0 km

ii. Second biker = 20.22 km

The path of travel of both bikers would form a triangle. Applying the Pythagoras theorem to the path of the first biker would give his distance from the starting point. While applying the cosine rule to the path of second rider would gives his distance to the starting point.

Thus,

a. To determine the distance of the first biker from the parking lot.

Let the required distance be represented by x. Applying the Pythagoras theorem, we have:

$hyp^{2}$ = $adj 1^{2}$ + $adj 2^{2}$

$x^{2}$ = $8^{2}$ + $15^{2}$

= 64 + 225

= 289

x = $\sqrt{289}$

= 17

x = 17 km

Thus, the first biker is 17.0 km from the starting point.

b. To determine the distance of the second biker from the parking lot.

Let the required distance be represented by x. So that applying the cosine rule, we have:

$c^{2}$ = $a^{2}$ + $b^{2}$ - 2ab Cos θ

$x^{2}$ = $8^{2}$ + $15^{2}$ - 2(15*8) Cos (180 - 20)

= 64 + 225 - 240 Cos 160

= 289 - 240 * -0.5

$x^{2}$ = 289 + 120

= 409

x = $\sqrt{409}$

= 20.2237

x = 20.22 km

Thus, the second biker is 20.22 km from the starting point.

Therefore, the second biker is farther from the parking lot.

A sketch of the path of travel for the two bikers is attached for more clarifications.

Visit: brainly.com/question/22699651

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2 years ago

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What angle corresponds to angle AFG?

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Look at the image below :)

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you have a work meeting that starts at 1:15 pm. you arrived at 12:53 pm. how many minutes early were you?

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I totally forgot that I am having meeting at my work place. All of sudden, I remembered that meeting through a hint given by my colleague while having discussion about our project work. I have to present a topic which I didn't prepare yet. Meeting is at 1.15pm. OMG! It's already 12.30 pm. Within few minutes I went to the meeting place with my topic. When I entered the meeting hall, the time was 12.53pm. I was happy to know that I arrived 22 minutes earlier.

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I need some help with this, please explain well. It's Trigonometry with right triangles, please let me know if you need a better

andreyandreev [35.5K]

Answer:

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4 years ago

Solve for b1176327160​

Solve for b1176327160