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pickupchik [31]

3 years ago

9

ethan school has a sports field with an area of 6450.35 square yards if the length of the field is 90.85 yards what is the width

of the field

1 answer:

enot [183]3 years ago

7 0

Area is found by multiplying the length by the width.

When the area and either the length or the width is known, you can find the missing dimension by dividing the total area by the known dimension.

6450.35 / 90.85 = 71

The width is 71 yards.

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The circumference of a circle is 37. 68 ft. What is the radius of the circle?.

mixer [17]

Answer:

r = 6 ft

Step-by-step explanation:

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2 years ago

Please help final exam

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3 years ago

How you know that the values of the digit in the numbers 1500,000 and 100,500 ate not the same

Sliva [168]

In this number 1500,000,

1 is at million place and 5 is at hundred thousand place

So, the value of 1 = 1 (1,000,000) = 1 million

And the value of 5 = 5 (100,000 ) = 500,000 = Five hundred thousand

In the second number 100,500

1 is at hundred thousand place and 5 is at hundred place

The value of 1 = 1 (100,000) = 100,000 = Hundred thousand

And the value of 5 = 5 (100 ) = 500 = Five hundred

Since the digits 1 and 5 both are at different places in both the numbers so 1,500,000 and 100,500 are not the same.

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3 years ago

Desperate need for help!<br> Maths!<br> Will award brainliest!

stealth61 [152]

Step-by-step explanation:

fg(x) =

${(x - 4)}^{2} + 3(x - 4)$

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4 0

3 years ago

A builder wants to build the bridge whose cross section is shown in the diagram. Two companies offer simple bids on building the

leva [86]

The length of the bridge is the distance from the beginning to the end.

<em>The distance b between each beam is 9ft.</em>

Let:

<em /> $I \to$ <em> I-Beam</em>

<em /> $d_I \to$ <em> distance between I beam and the bridge</em>

<em /> $b \to$ <em> distance between each I beam</em>

<em />

Given that:

$I = \frac 34 ft\\$

$d_I = 3 ft$

<em /> $Length = 55ft\ 6in$ <em> --- length of the bridge</em>

<em />

From the diagram (see attachment), there are: 6 I-beams.

So, the length of the 6 I-beams is:

$L_1 = 6 \times I$

$L_1 = 6 \times \frac 34$

$L_1 = \frac {18}4$

$L_1 = 4.5ft$

There are 2 I-beams beside the bridge

So, the distance between the 2 I-beams and the bridge is:

$d_1 =2 \times d_I$

$d_1 =2 \times 3ft$

$d_1 =6ft$

There are 5 spaces between the I-beams

So, the length of the total spaces is:

$L_2 = 5 \times b$

$L_2 = 5b$

The total length is:

$Length = L_1 + d_1 + L_2$

So, we have:

$4.5ft + 6ft + 5b = 55ft\ 6in$

Collect like terms

$5b = 55ft\ 6in - 4.5ft - 6ft$

$5b = 44.5ft\ 6in$

Convert inches to feet

$5b = 44.5ft\ + \frac{6}{12}ft$

$5b = 44.5ft\ + 0.5ft$

$5b = 45ft$

Divide both sides by 5

$b = 9ft$

<em>Hence, the distance (b) between each beam is 9ft.</em>

Read more about lengths at:

brainly.com/question/22059747

3 0

3 years ago