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▹ Answer
<em>A. Statistical</em>
▹ Step-by-Step Explanation
Since you are asking about how many acorns squirrels typically eat in a day, you are asking for how many acorns on average. Average can be shown in statistical graphs therefore, making the answer statistically.
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Answer:
The 95% confidence interval of the true mean.
(29.4261 ,36.9739)
Step-by-step explanation:
<u>Step :- (i)</u>
Given sample size 'n' =15
sample of the mean x⁻ = 33.2
The standard deviation of the sample 'S' = 8.3
<u>95% of confidence intervals</u>
<u></u>
<u></u>
<u>Step:-(ii)</u>
<u>The degrees of freedom γ=n-1 = 15-1=14</u>
The tabulated value t = 1.761 at 0.05 level of significance.
now substitute all possible values, we get

After calculation , we get
(33.2-3.7739 , 33.2+3.7739
(29.4261 ,36.9739)
<u>Conclusion</u>:-
the 95% confidence interval of the true mean.
(29.4261 ,36.9739)
<span><span>f<span>(x)</span>=8x−6</span><span>f<span>(x)</span>=8x-6</span></span> , <span><span>[0,3]</span><span>[0,3]
</span></span>The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.<span><span>(−∞,∞)</span><span>(-∞,∞)</span></span><span><span>{x|x∈R}</span><span>{x|x∈ℝ}</span></span><span><span>f<span>(x)</span></span><span>f<span>(x)</span></span></span> is continuous on <span><span>[0,3]</span><span>[0,3]</span></span>.<span><span>f<span>(x)</span></span><span>f<span>(x)</span></span></span> is continuousThe average value of function <span>ff</span> over the interval <span><span>[a,b]</span><span>[a,b]</span></span> is defined as <span><span>A<span>(x)</span>=<span>1<span>b−a</span></span><span>∫<span>ba</span></span>f<span>(x)</span>dx</span><span>A<span>(x)</span>=<span>1<span>b-a</span></span><span>∫ab</span>f<span>(x)</span>dx</span></span>.<span><span>A<span>(x)</span>=<span>1<span>b−a</span></span><span>∫<span>ba</span></span>f<span>(x)</span>dx</span><span>A<span>(x)</span>=<span>1<span>b-a</span></span><span>∫ab</span>f<span>(x)</span>dx</span></span>Substitute the actual values into the formula for the average value of a function.<span><span>A<span>(x)</span>=<span>1<span>3−0</span></span><span>(<span>∫<span>30</span></span>8x−6dx)</span></span><span>A<span>(x)</span>=<span>1<span>3-0</span></span><span>(<span>∫03</span>8x-6dx)</span></span></span>Since integration is linear, the integral of <span><span>8x−6</span><span>8x-6</span></span> with respect to <span>xx</span> is <span><span><span>∫<span>30</span></span>8xdx+<span>∫<span>30</span></span>−6dx</span><span><span>∫03</span>8xdx+<span>∫03</span>-6dx</span></span>.<span><span>A<span>(x)</span>=<span>1<span>3−0</span></span><span>(<span>∫<span>30</span></span>8xdx+<span>∫<span>30</span></span>−6dx)</span></span><span>A<span>(x)</span>=<span>1<span>3-0</span></span><span>(<span>∫03</span>8xdx+<span>∫03</span>-6dx)</span></span></span>Since <span>88</span> is constant with respect to <span>xx</span>, the integral of <span><span>8x</span><span>8x</span></span> with respect to <span>xx</span> is <span><span>8<span>∫<span>30</span></span>xdx</span><span>8<span>∫03</span>xdx</span></span>.<span><span>A<span>(x)</span>=<span>1<span>3−0</span></span><span>(8<span>∫<span>30</span></span>xdx+<span>∫<span>30</span></span>−6dx)</span></span><span>A<span>(x)</span>=<span>1<span>3-0</span></span><span>(8<span>∫03</span>xdx+<span>∫03</span>-6dx)</span></span></span>By the Power Rule, the integral of <span>xx</span> with respect to <span>xx</span> is <span><span><span>12</span><span>x2</span></span><span><span>12</span><span>x2</span></span></span>.<span>A<span>(x)</span>=<span>1<span>3−0</span></span><span>(8<span>(<span><span>12</span><span>x2</span><span>]<span>30</span></span></span>)</span>+<span>∫<span>30</span></span>−6dx<span>)</span></span></span>
Answer:
this is just for part A sorry i dont get part B
oof bad drawing of a trapezoid
The expression of the inequality word problems for each question is; As expressed below
<h3>How to express inequalities?</h3>
A) x is negative. This can be expressed as;
x < 0
B) y is non-negative. This can be expressed as;
y > 0
C) q is less than or equal to is expressed as; q ≤
D) d is between 2 and 1 is expressed as 1 < d < 2
E) t is not less than 5 is t ≥ 5
F) The negative of z is not greater than 3 is expressed as;
−z ≤ 3
G) The quotient of p and q is at most 6 is expressed as; p/q ≤ 6
H) The reciprocal of w is at least 9 is 1/w ≥ 9.
Read more about Inequalities at; brainly.com/question/24372553
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