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3 years ago

How would you describe this pattern's rule? 65, 62, 59, 56, 53,50

Mathematics

2 answers:

const2013 [10]3 years ago

7 0

Answer:subtracting

Step-by-step explanation:

LiRa [457]3 years ago

6 0

You are subtracting 3 each time. (-3)

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What is the value of n so that the expression x2 11x n is a perfect square trinomial

saw5 [17]

Answer:

$n=\frac{121}{4}$

Step-by-step explanation:

Since we know that perfect square trinomial formula states that any trinomial of the form $ax^{2} +bx+c$ is said to a perfect square if it satisfies the condition $b^{2} =4ac$ .

We are given an expression $x^{2} ?11x ?n$ and asked to find value of n for expression to be a perfect square trinomial .

Let us compare our expression with perfect square trinomial formula.

We can see that a=1, b=11 and c=n.

Let us find value of n by substituting our given values in $b^{2} =4ac$ .

$11^{2} =4*1*n$

$121 =4n$ .

$n=\frac{121}{4}$

Therefore, $n=\frac{121}{4}$ will make the expression $x^{2} ?11x ?n$ a perfect square trinomial.

6 0

3 years ago

I need help ASAP on number 21

Nostrana [21]

Answer:

Step-by-step explanation:

It lines up with the intersection of the two lines

3 0

3 years ago

Find the taylor series for f(x centered at the given value of

Lady_Fox [76]

To find the Taylor series for f(x) = ln(x) centering at 5, we need to observe the pattern for the first four derivatives of f(x). From there, we can create a general equation for f(n). Starting with f(x), we have

$f(x) = ln(x) \\ f^{1}(x) = \frac{1}{x} \\ f^{2}(x) = -\frac{1}{x^{2}} \\ f^{3}(x) = \frac{2}{x^{3}} \\ f^{4}(x) = \frac{-6}{x^{4}}$
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.
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Since we need to have it centered at 5, we must take the value of f(5), and so on.

$f(5) = ln(5) \\ f^{1}(5) = \frac{1}{5} \\ f^{2}(5) = \frac{-1}{5^{2}} \\ f^{3}(5) = \frac{1(2)}{5^{3}} \\ f^{4}(5) = \frac{-1(2)(3)}{5^{4}}$
.
.
.
Following the pattern, we can see that for $f^{n}(x)$ ,

$f^{n}(x) = (-1)^{n-1} \frac{1(2)(3)...(n-1)}{5^{n}} \\ f^{n}(x) = (-1)^{n-1} \frac{(n-1)!}{5^{n}}$

This applies for $n\geq 1$ . Expressing f(x) in summation, we have

$\sum_{n=0}^{\infty} \frac{f^{n}(5)}{n!} (x-5)^{n}$

Combining ln2 with the rest of series, we have

$f(x) = ln2 + \sum_{n=1}^{\infty} (-1)^{n-1} \frac{(n-1)!}{(n!)(5^{n})} (x-5)^{n}$
<span>
Answer: </span> $f(x) = ln2 + \sum_{n=1}^{\infty} (-1)^{n-1} \frac{(n-1)!}{(n!)(5^{n})} (x-5)^{n}$

3 0

3 years ago

-53.1 as a mixed number

horsena [70]

-53 1/10 because .1=1/10

3 0

4 years ago

Read 2 more answers

What is the equation of a line that passes through the points (3,3) and (-3,7)

just olya [345]

Answer:

slope intercept form is y=-2/3x+5

6 0

3 years ago