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sveticcg [70]
3 years ago
13

Which property of real numbers is illustrated by the following statement? 6(7x) = (6 ∙ 7)x

Mathematics
1 answer:
romanna [79]3 years ago
3 0
<span>6(7x) = (6 ∙ 7)x
</span>
answer
Associative Property of Multiplication
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Solve the equation -4 + 4a = 12 for a.
WARRIOR [948]

Hello there! The answer to your question is a = 4.

To solve for a in the equation -4 + 4a = 12 you want to isolate, or separate, a from all of the equation's other values.

Our first step is to add 4 to both sides so the 4 cancels out on the left side.

-4+4 + 4a = 12+4

4a = 16

Next, we divide both sides by 4 to finish isolating a.

4/4a = 16/4

a = 4

Want to verify that this is correct? Place the value we found for a (4) into the equation in place of a and if it comes out as a true statement, the answer is correct.

-4 + 4(4) = 12

-4 + 16 = 12

12 = 12

Since 12 is in fact equal to 12, i can guarantee you that i have provided you with the correct answer. I hope this helps & have a great rest of your day! :)

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2 years ago
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Solve the inequality. Graph the solution.<br><br> w+6≤−3
yuradex [85]

Answer: w<-9 With the line underneath

Step-by-step explanation:

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3 years ago
Helppp meeee plssss with this pls
Darina [25.2K]
It’s the letter “B” I think
8 0
3 years ago
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Here is a rectangle ABCD.
lana66690 [7]

Answer:

32%

Step-by-step explanation:

Area of rectangle ABCD = 20 * 30 = 600 Sq cm

After increasing the length and width of the rectangle by 20% and 10% respectively.

New length = 30 + 20% of 30 = 30 + 6 = 36 cm

New width = 20 + 10% of 20 = 20 + 2 = 22 cm

Area of new rectangle = 36*22 = 792 Sq cm

Increase in area = 792 - 600 = 192 Sq cm

Percentage increase in area

= (192/600) *100

= 32%

5 0
3 years ago
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What is the "k" value of the following function? Is it 3, -2, -3, or 2?
snow_tiger [21]

Answer:

-3

Step-by-step explanation:

we khow that the vertex form of a function is written this way :

f(x)=a(x-h)²+k

  • the coordinates of the vertex are (h,k) so from the graph we can deduce that k = -3

5 0
3 years ago
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