Question

Can someone help me solve these questions?

Answer 1

Answer:

0, 5, 8, 11

Step-by-step explanation:

(a)

f(0) → x = 0 in interval - 2 ≤ x < 1 , thus x³ , that is

0³ = 0 ⇒ f(0) = 0

(b)

f(1) → x = 1 in interval 1 ≤ x ≤ 4, thus 3x + 2, that is

f(1) = 3(1) + 2 = 3 + 2 = 5

(c)

f(2) → x = 2 in interval 1 ≤ x ≤ 4, that is

f(2) = 3(2) + 2 = 6 + 2 = 8

(d)

f(3) → x = 3 in interval 1 ≤ x ≤ 4, that is

f(3) = 3(3) + 2 = 9 + 2 = 11