Answer:
0, 5, 8, 11
Step-by-step explanation:
(a)
f(0) → x = 0 in interval - 2 ≤ x < 1 , thus x³ , that is
0³ = 0 ⇒ f(0) = 0
(b)
f(1) → x = 1 in interval 1 ≤ x ≤ 4, thus 3x + 2, that is
f(1) = 3(1) + 2 = 3 + 2 = 5
(c)
f(2) → x = 2 in interval 1 ≤ x ≤ 4, that is
f(2) = 3(2) + 2 = 6 + 2 = 8
(d)
f(3) → x = 3 in interval 1 ≤ x ≤ 4, that is
f(3) = 3(3) + 2 = 9 + 2 = 11
