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FinnZ [79.3K]
3 years ago
6

- 3(x - 1) + 8(x - 3) = 6x + 7 - 5x short solve it plz

Mathematics
2 answers:
g100num [7]3 years ago
6 0

Answer:

x=-28

Step-by-step explanation:

-3(x-1)+8(x-3)=6x+7

1) Distribute -3 to x and -1:

-3x+3

2) Distribute 8 to x and -3:

-3x+3+8x-24=6x+7

3) Combine alike terms:

5x-21=6x+7

4) Subtract 5x from both sides:

-21=x+7

5) Subtract 7 from both sides:

x=-28

Footnotes:

The <u>Distributive</u> property says a(b+c)=ab+ac

Drupady [299]3 years ago
4 0

Answer:

no it = -3x +3 + 8x - 24 = 5x + 21

Step-by-step explanation:

i think u dont need explaination so...

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Find the area of the region that lies under the parabola y=5x - x^2, where 1≤x≤4. I would definitely like to see some work :)
Elena L [17]

Answer:

  16.5 square units

Step-by-step explanation:

You are expected to integrate the function between x=1 and x=4:

  \displaystyle\text{area}=\int_1^4{(5x-x^2)}\,dx=\left.\left(\dfrac{5}{2}x^2-\dfrac{1}{3}x^3\right)\right|_{x=1}^{x=4}\\\\=\dfrac{5(4^2-1^2)}{2}-\dfrac{4^3-1^3}{3}=37.5-21=\boxed{16.5}

__

<em>Additional comment</em>

If you're aware that the area inside a (symmetrical) parabola is 2/3 of the area of the enclosing rectangle, you can compute the desired area as follows.

The parabolic curve is 4-1 = 3 units wide between x=1 and x=4. It extends upward 2.25 units from y=4 to y=6.25, so the enclosing rectangle is 3×2.25 = 6.75 square units. 2/3 of that area is (2/3)(6.75) = 4.5 square units.

This region sits on top of a rectangle 3 units wide and 4 units high, so the total area under the parabolic curve is ...

  area = 4.5 +3×4 = 16.5 . . . square units

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2 years ago
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