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vfiekz [6]
3 years ago
6

Consider the formula for glucose: C6H12O6. What does this indicate about the relationship of the reactants to glucose?

Chemistry
2 answers:
HACTEHA [7]3 years ago
8 0

Answer: Option (D) is the correct answer.

Explanation:

Formation of glucose occurs due to a chemical reaction taking place in plants known as photosynthesis.

Therefore, photosynthesis is defined as a chemical process in which plants tend to make their own food in the presence of sunlight, water and carbon dioxide.

During this process, product formed by the plants is glucose and oxygen.

The chemical reaction equation for photosynthesis is as follows.

      6CO_{2} + 6H_{2}O + \text{Sunlight} \rightarrow C_{6}H_{12}O_{6} + 6O_{2}

Thus, we can conclude that the statement six carbon dioxide (CO_{2}) molecules were used to make it, indicate about the relationship of the reactants to glucose.

stellarik [79]3 years ago
6 0

The correct option is D.

The reactants that combine together to form glucose are carbon dioxide, water and energy from the sun. Six molecules of carbon dioxide combine with six molecules of water in the presence of sunlight to form glucose. The chemical equation for the reaction is given below"

6CO2 + 6H2O + Sunlight = C6H12O6.

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If two gases a and b in separate 1 liter containers
Anton [14]

The pressure exerted when both gases are put together in a single 1 liter container is 5 atm.

<h3>What is pressure?</h3>

Pressure is the force exerted by any object on another object.

Given that, a and b separate 1 liter containers and exert pressure of 2 atm and 3 atm respectively.

When both gases a and b exert together, the pressure then

2 atm + 3 atm = 5 atm.

Thus, the pressure exerted when both gases are put together in a single 1 liter container is 5 atm.

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7 0
2 years ago
PLS help
viktelen [127]

Answer:

d . Sc2O5

Explanation:

Hello,

In this case, when forming oxides from a metal and oxygen, for us to find out each element's subscript, we must exchange them as shown below, considering +5 for scandium:

Sc^{+5}_2O^{-2}_5

For that reason, the answer is d . Sc2O5

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3 0
3 years ago
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Aniline is produced by the hydrogenation of nitrobenzene. a small amount of cyclo-hexylamine is produced as a byproduct. the rea
Tom [10]

Aniline can be produced from nitro-benzene by reduction. When nitro-benzene reacts with tin (Sn) + hydrochloride acid (HCl) then aniline is produced. The Sn + HCl forms free hydrogen ions which converts the nitro group of the benzene ring to amine group, which is aniline. In place of Sn + HCl. One can use palladium (Pd) hydrogen mixture in presence of ethanol (EtOH). There produces a side product in this reaction which is cyclohexyl amine. The reaction can be shown as.

8 0
3 years ago
At a given temperature, the elementary reaction A − ⇀ ↽ − B , A↽−−⇀B, in the forward direction, is first order in A A with a rat
Svetllana [295]

Answer:

The equilibrium constant for the reversible reaction = 0.0164

Explanation:

At equilibrium the rate of forward reaction is equal to the rate of backwards reaction.

The reaction is given as

A ⇌ B

Rate of forward reaction is first order in [A] and the rate of backward reaction is also first order in [B]

The rate of forward reaction = |r₁| = k₁ [A]

The rate of backward reaction = |r₂| = k₂ [B]

(Taking only the magnitudes)

where k₁ and k₂ are the forward and backward rate constants respectively.

k₁ = 0.010 s⁻¹

k₂ = 0.0610 s⁻¹

|r₁| = 0.010 [A]

|r₂| = 0.016 [B]

At equilibrium, the rate of forward and backward reactions are equal

|r₁| = |r₂|

k₁ [A] = k₂ [B] (eqn 1)

Note that equilibrium constant, K, is given as

K = [B]/[A]

So, from eqn 1

k₁ [A] = k₂ [B]

[B]/[A] = (k₁/k₂) = (0.01/0.0610) = 0.0163934426 = 0.0164

K = [B]/[A] = (k₁/k₂) = 0.0164

Hope this Helps!!!

5 0
3 years ago
What are two methods of writing a balanced formula?
Irina-Kira [14]
Format Method - Writing the symbol of the cation and then the anion. Add whatever subscripts in order to balance the charges.

Crisscross Method - The numerical value of the charge of each ion is crossed over and becomes the subscripts for the other ion.
8 0
4 years ago
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