The answer is pull your welcome
Answer:
Remain unchanged.
Explanation:
The total number of moles of liquid remain unchanged as the some moles of species B are added to the system because specie B that is added in the liquid phase is again restored after addition. If the specie B did not restored after addition to the liquid phase so the total number of moles increases in the liquid phase so that's why we can say that the liquid phase remain unchanged.
Answer is: <span>fewer drops of 6 M sulfuric acid, because concentration of H</span>⁺ is greater than in hydrochloric acid with same concentration.<span>
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Chemical dissociation of hydrochloric acid in water:
HCl(aq) → H⁺(aq) + Cl⁻(aq).
Chemical dissociation of sulfuric acid in water:
H₂SO₄(aq) → 2H⁺(aq) + SO₄²⁻(aq).
From chemical reaction: c(HCl) = c(H⁺) = 6 M.
c(H⁺) = 2c(H₂SO₄) = 2 · 6 M = 12 M; concentration of hydrogen cations.
Answer:
The answer to your question is below
Explanation:
Data
[HBr] = 0.045 M
[H⁺] = ?
[OH⁻] = ?
pH = ?
pOH = ?
Process
1.- Determine the [H⁺]
The [H⁺] is equal to the [HBr] then, [H⁺] = 0.045 M
2.- Determine the pH
pH = -log[H⁺]
-Substitution
pH = -log[0.045]
-Result
pH = 1.35
3.- Determine the pOH
Formula
pH + pOH = 14
-Solve for pOH
pOH = 14 - pH
-Substitution
pOH = 14 - 1.35
-Result
pOH = 12.65
4.- Determine the [OH⁻]
pOH = -log[OH⁻]
-Solve for [OH⁻]
[OH⁻] = antilog(-pOH)
-Substitution
[OH⁻] = antilog (-12.65)
-Result
[OH⁻] = 2.22 x 10⁻¹³