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Annette [7]
3 years ago
9

5. What is the distance of something from side to side?

Chemistry
1 answer:
Sav [38]3 years ago
6 0

Answer:

Distance of something it can be any type of distance

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Student 1You are supplied with a 100 mL beaker that you weigh on a pocket balance – its weight clean and dry is 29.3 g. You then
navik [9.2K]

Answer:

The answer to your question is: density = 0.993 g/ml

Explanation:

Data

mass beaker empty = 29.3 g

volume of liquid = 15 ml

mass beaker + liquid = 44.2 g

Formula

             density = mass / volume

Process

mass of liquid = 44.2 - 29.3

                       = 14.9 g

             density = 14.9 / 15

                          = 0.993 g/ml

6 0
3 years ago
Is the chemical reaction between magnesium metal and hydrochloric acid solution an acid base reaction?
Anika [276]

Answer:

No

Explanation:

The chemical reaction between magnesium metal and hydrochloric acid solution is not an acid - base reaction.

An acid - base reaction involves an acid and base to produce salt and water.

  • This reaction is called a neutralization reaction.
  • An acid is a substance that produces excess hydroxonium ions in solutions.
  • A base produces excess hydroxyl ions in solution.
  • When acids and base combines, the main product is a salt in water solution.

3 0
2 years ago
Phosgene, a poisonous gas, when heated will decompose into carbon monoxide and chlorine in a reversible reaction: COCl2 (g) <
Advocard [28]

Answer:

8.08 × 10⁻⁴

Explanation:

Let's consider the following reaction.

COCl₂(g) ⇄ CO (g) + Cl₂(g)

The initial concentration of phosgene is:

M = 2.00 mol / 1.00 L = 2.00 M

We can find the final concentrations using an ICE chart.

     COCl₂(g) ⇄ CO (g) + Cl₂(g)

I       2.00            0            0

C        -x             +x           +x

E    2.00 -x          x             x

The equilibrium concentration of Cl₂, x, is 0.0398 mol / 1.00 L = 0.0398 M.

The concentrations at equilibrium are:

[COCl₂] = 2.00 -x = 1.96 M

[CO] = [Cl₂] = 0.0398 M

The equilibrium constant (Keq) is:

Keq = [CO].[Cl₂]/[COCl₂]

Keq = (0.0398)²/1.96

Keq = 8.08 × 10⁻⁴

4 0
3 years ago
How many sulfur atoms are expected in the reactants of this chemical reaction?
Rudik [331]
Answer is B, because CaSO3 only has one S
4 0
3 years ago
Consider the following reaction:
adell [148]

Answer:

1. d[H₂O₂]/dt = -6.6 × 10⁻³ mol·L⁻¹s⁻¹; d[H₂O]/dt = 6.6 × 10⁻³ mol·L⁻¹s⁻¹

2. 0.58 mol

Explanation:

1.Given ΔO₂/Δt…

    2H₂O₂     ⟶      2H₂O     +     O₂

-½d[H₂O₂]/dt = +½d[H₂O]/dt = d[O₂]/dt  

d[H₂O₂]/dt = -2d[O₂]/dt = -2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ = -6.6 × 10⁻³mol·L⁻¹s⁻¹

 d[H₂O]/dt =  2d[O₂]/dt =  2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ =  6.6 × 10⁻³mol·L⁻¹s⁻¹

2. Moles of O₂  

(a) Initial moles of H₂O₂

\text{Moles} = \text{1.5 L} \times \dfrac{\text{1.0 mol}}{\text{1 L}} = \text{1.5 mol }

(b) Final moles of H₂O₂

The concentration of H₂O₂ has dropped to 0.22 mol·L⁻¹.

\text{Moles} = \text{1.5 L} \times \dfrac{\text{0.22 mol}}{\text{1 L}} = \text{0.33 mol }

(c) Moles of H₂O₂ reacted

Moles reacted = 1.5 mol - 0.33 mol = 1.17 mol

(d) Moles of O₂ formed

\text{Moles of O}_{2} = \text{1.33 mol H$_{2}$O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{2 mol H$_{2}$O}_{2}} = \textbf{0.58 mol O}_{2}\\\\\text{The amount of oxygen formed is $\large \boxed{\textbf{0.58 mol}}$}

8 0
3 years ago
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