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GalinKa [24]
3 years ago
13

If a sample of oxygen gas originally at from 171.4 K has its temperature increased to 288.4 K and

Chemistry
1 answer:
julia-pushkina [17]3 years ago
6 0

Answer:

V₂ = 0.95 L

Explanation:

Given data:

Initial temperature of gas = 171.4 K

Final temperature of gas = 288.4 K

Final volume = 1.6 L

Initial volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₁ = V₂T₁ /T₂

V₂ = 1.6 L × 171.4 K / 288.4 k

V₂ = 274.24 L.K / 288.4 K

V₂ = 0.95 L

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tiny-mole [99]
<h3>Answer:</h3>

6.26 g C

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 3.14 × 10²³ atoms C

[Solve] grams C

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of C - 12.01 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                      \displaystyle 3.14 \cdot 10^{23} \ atoms \ C(\frac{1 \ mol \ C}{6.022 \cdot 10^{23} \ atoms \ C})(\frac{12.01 \ g \ C}{1 \ mol \ C})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 6.26227 \ g \ C

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

6.26227 g C ≈ 6.26 g C

7 0
3 years ago
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Answer:

Air is less dense on a mountaintop than at sea level.

Air pressure is lower at low altitudes.

As you climb a mountain, air pressure increases.

More force pushes on the air at the bottom of an air column.

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Explanation:

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3 years ago
Write a balanced nuclear equation for the following: The nuclide astatine-218 undergoes alpha emission to give bismuth-214
galina1969 [7]

Answer:

^{218}_{85}At\rightarrow ^{214}_{83}Bi+^{4}_{2}He

Explanation:

Hello there!

In this case, since the radioactive reaction for the alpha emission of astatine-218 to bismith-214 involve the release of a helium atom as shown below:

^{218}_{85}At\rightarrow ^{214}_{83}Bi+^{4}_{2}He

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7 0
3 years ago
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Time taken for star to reach Earth = 7.5 years

<h3>Further explanation</h3>

Given

7.5 light years(distance Earth-star)

Required

Time taken

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1 light years = 9.461 × 10¹⁵ m= distance(d)

So time taken for 1 light years :

time(t) = distance(d) : speed(v)

t = 9.461 × 10¹⁵ m : 3 x 10⁸ m/s

t = 3.154 x 10⁷ s = 1 years

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