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GalinKa [24]
2 years ago
13

If a sample of oxygen gas originally at from 171.4 K has its temperature increased to 288.4 K and

Chemistry
1 answer:
julia-pushkina [17]2 years ago
6 0

Answer:

V₂ = 0.95 L

Explanation:

Given data:

Initial temperature of gas = 171.4 K

Final temperature of gas = 288.4 K

Final volume = 1.6 L

Initial volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₁ = V₂T₁ /T₂

V₂ = 1.6 L × 171.4 K / 288.4 k

V₂ = 274.24 L.K / 288.4 K

V₂ = 0.95 L

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How many grams are in 4.0 moles of lithium
Fittoniya [83]

Answer:

The correct answer is 27.764 grams.

Explanation:

A standard scientific unit for determining the large quantities of very small entities like molecules, atoms, or other specific particles is termed as a mole. The molecular weight of lithium is 6.941 grams per mole. Thus, one mole of lithium has 6.941 grams.

If, 1 mole of Li has 6.941 grams, then 4 moles of Lithium will have,

= Molecular mass of lithium/1 mole * 4 mole

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2 years ago
Alexandra decides to climb Mt. Krumpett, which is 5000 m high. She determines that this will require a total of 1350 kcal of ene
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8 0
3 years ago
Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 4.1 g of butane is m
m_a_m_a [10]

Answer:

12.44 g

Explanation:

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n(O2) = m(O2)/M(O2) = 25.9 / 32g/mol = 0.809 mol (deficiency).

Since the ratio of O2 to octane is 13 : 2 we can divide 0.0707 by 2 to get 0.03535 and divide 0.809 by 13 to get 0.062.

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M = 12.44 of CO2

5 0
2 years ago
In the periodic table, the elements are organized into groups based on
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<span>In the periodic table, the elements are organized into groups based on putting together elements with similar properties. For instance, elements in each group have the same number of valence electrons, which makes them form similar bonds. Additionally, elements in the same similar characteristics, such as malleability and magnetism.</span>
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4 0
2 years ago
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