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Nimfa-mama [501]
3 years ago
10

Can I get some help with this question plzzz

Mathematics
1 answer:
victus00 [196]3 years ago
7 0
All the possible combinations are
1-1 2-1 3-1 4-1 5-1 6-1
1-2. 2-2 3-2 4-2. 5-2. 6-2
1-3 2-3. 3-3. 4-3. 5-3. 6-3
1-4. 2-4. 3-4. 4-4. 5-4. 6-4
1-5. 2-5. 3-5. 4-5. 5-5. 6-5
1-6. 2-6. 3-6. 4-6. 5-6. 6-6

What is the total for each roll?

2. 3. 4. 5. 6. 7.
3. 4. 5. 6. 7. 8
4. 5. 6. 7. 8. 9
5. 6. 7. 8. 9. 10.
6. 7. 8. 9. 10. 11.
7. 8. 9. 10. 11. 12

What roll occurs most often?

>>>>>>7<<<<<

7 occurs in 6 out of 36 possible outcomes
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Answer:

The answer in each numeral is:

  1. <u>f(4) = 28</u>
  2. <u>f(10) = -19</u>
  3. <u>f(-5) = -33</u>
  4. <u>f(9) = -9</u>

Step-by-step explanation:

To obtain the result in each case, you must replace the variable (n) by the value that appears in the second case, I'll explain it with the first exercise:

  • 1. f(n) = 5n + 8
  •   f(4) = ?

As you can see, in the second doesn't appear f(n), but f(4), that means you must replace the "n" in the equation by 4, if we do this, we obtain:

  • 1. f(4) = 5*(4) + 8
  • f(4) = 20 + 8
  • <u>f(4) = 28</u>

The first answer is 28, now we'll continue with the next exercises:

  • 2. f(n) = -2n + 1
  • f(10) = -2*(10) + 1
  • f(10) = -20 + 1
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  • 3. f(n) = 6n - 3
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  • f(-5) = -30 - 3
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  • 4. f(n) = -n
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In this form, <u><em>you can prove the answers are: 28, -19, -33, and -9 respectively</em></u>.

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