Plot the points A(-2.-3), B(-3,0) C(3,2) and D(4,-1) what type of quadrilateral is abcd?

Please help!! I’ve been struggling for days.

Tomtit [17]

Answer:

y=-1/4x-6

Step-by-step explanation:

y intercept is -6 and slope is -1/4

point slope is y-y1=m(x-x1)

you can use and point. i am using (0,-6)

y--6=-1/4(x-0)

y+6=-1/4x

-6 -6

y=-1/4x-6

7 0

2 years ago

X + 3/2= 2 1/4 whats the answer

kicyunya [14]

Move all terms not containing x to the right side of the equation.

Exact Form:

x=15/4

Decimal Form:

x=3.75

Mixed Number Form:

x=3 3/4

hope this helps

5 0

1 year ago

Please help I am so confused

Ede4ka [16]

The total cost when 881 minutes is used is $477.50.

<h3>What are the equation that model the question?</h3>

a + 480b = 277 equation 1

a + 990b = 532 equation 2

Where:

a = flat fee
b = variable fee

<h3>What is the flat fee and the variable fee?</h3>

Subtract equation 1 from equation 2

510b = 255

b = 255 / 510

b = $0.50

In order to determine the flat fee, substitute for b in equation 1

a + 480(0.5) = 277

a + 240 = 277

a = 277 - 240

a = $37

<h3>What is the total cost when 881 minutes is used?</h3>

Total cost = flat fee + (variable cost x number of minutes spoken)

$37 + (881 x 0.5) = $477.50

To learn more about simultaneous equations, please check: brainly.com/question/25875552

#SPJ1

7 0

1 year ago

What’s the correct answer answer asap for brainlist

svetlana [45]

Answer:

Iron

Step-by-step explanation:

Just learned about this

6 0

1 year ago

Read 2 more answers

Find a cubic function with the given zeros.

Fed [463]

Answer:

The correct option is D) $f(x) = x^3 + 2x^2 - 2x - 4$ .

Step-by-step explanation:

Consider the provided cubic function.

We need to find the equation having zeros: Square root of two, negative Square root of two, and -2.

A "zero" of a given function is an input value that produces an output of 0.

Substitute the value of zeros in the provided options to check.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x + 4$ .

$f(x) = x^3 + 2x^2 - 2x + 4\\f(x) = (-2)^3 + 2(-2)^2 - 2(-2) + 4\\f(x) =-8 + 2(4)+4 + 4\\f(x) =8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 + 2x - 4$ .

$f(x) = x^3 + 2x^2 + 2x - 4\\f(x) = (-2)^3 + 2(-2)^2 + 2(-2) - 4\\f(x) =-8+2(4)-4-4\\f(x) =-8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 - 2x^2 - 2x - 4$ .

$f(x) = x^3 - 2x^2 - 2x - 4\\f(x) = (-2)^3 - 2(-2)^2 - 2(-2) - 4\\f(x) =-8-8+4-4\\f(x) =-16$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-2)^3+2(-2)^2 - 2(-2) - 4\\f(x) =-8+8+4-4\\f(x) =0$

Now check for other roots as well.

Substitute x=√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (\sqrt{2})^3+2(\sqrt{2})^2 - 2(\sqrt{2}) - 4\\f(x) =2\sqrt{2}+4-2\sqrt{2}-4\\f(x) =0$

Substitute x=-√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-\sqrt{2})^3+2(-\sqrt{2})^2 - 2(-\sqrt{2}) - 4\\f(x) =-2\sqrt{2}+4+2\sqrt{2}-4\\f(x) =0$

Therefore, the option is correct.

8 0

3 years ago