Answer:
First five terms are:
8 , (-4) , 2 , (-1) , (1/2)
Step-by-step explanation:
<span>Perimeter =2w+2L= 520.
We can solve this by understanding that the area is maximized by a square
Therefore L=w.
p=2w+2w=520=4w
w=130
Area
A=wL=130(130)= 16900 square yards</span>
(2x² - 5) - (3x² + 4).
Pretend that there is a -1 in front of :(3x² + 4).
(2x^2-5)-1(3x^2+4)
2x^2-5-3x^-4
2x^2-3x^2-5-4
=-x^2-9
Answer: -x^2-9
13x - 4 < 12(x-1)
13x - 4 < 12x - 12
13x - 12x < -12 + 4
x < -8
x > 8
x is greater than 8
The function "choose k from n", nCk, is defined as
nCk = n!/(k!*(n-k)!) . . . . . where "!" indicates the factorial
a) No position sensitivity.
The number of possibilities is the number of ways you can choose 5 players from a roster of 12.
12C5 = 12*11*10*9*8/(5*4*3*2*1) = 792
You can put 792 different teams on the floor.
b) 1 of 2 centers, 2 of 5 guards, 2 of 5 forwards.
The number of possibilities is the product of the number of ways, for each position, you can choose the required number of players from those capable of playing the position.
(2C1)*(5C2)*(5C2) = 2*10*10 = 200
You can put 200 different teams on the floor.
