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Nata [24]
3 years ago
5

Using the given zero, find all other zeros of f(x).

Mathematics
1 answer:
WINSTONCH [101]3 years ago
6 0
Hello : 
answer : a 
 because : f(2i) = (2i)^4 -45(2i)² -196 = 16(1)-45(-4)-196...... ( i²=-1) 
                          = 16+180 -196 =196-196 =0
same solution : f(14i)=f(-14i)=0
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Write the first five terms of the geometric sequence in which a1=8 and the common ratio is -1/2.
Oliga [24]

Answer:

First five terms are:

8 , (-4) , 2 , (-1) , (1/2)

Step-by-step explanation:

a_{1}=8 \\\\r = \frac{-1}{2}\\\\a_{2}=\frac{-1}{2}*a_{1}= \frac{-1}{2}*8= -4\\\\a_{3}=\frac{-1}{2}*a_{2}=\frac{-1}{2}*-4=2\\\\a_{4}=\frac{-1}{2}*a_{3}=\frac{-1}{2}*2=-1\\\\a_{5}=\frac{-1}{2}*a_{4}=\frac{-1}{2}*-1=\frac{1}{2}

4 0
3 years ago
Alex has 520 yards of fencing to enclose a rectangular area.
Pavlova-9 [17]
<span>Perimeter =2w+2L= 520.
We can solve this by understanding that the area is maximized by a square
Therefore L=w.

p=2w+2w=520=4w
w=130

Area
 
A=wL=130(130)= 16900 square yards</span>
6 0
3 years ago
Read 2 more answers
(2x² - 5) - (3x² + 4).
Goshia [24]

(2x² - 5) - (3x² + 4).

Pretend that there is a -1 in front of :(3x² + 4).

(2x^2-5)-1(3x^2+4)

2x^2-5-3x^-4

2x^2-3x^2-5-4

=-x^2-9

Answer: -x^2-9

3 0
3 years ago
Solve 13x - 4 &lt; 12(x - 1).
Effectus [21]
13x - 4 < 12(x-1)
13x - 4 < 12x - 12
13x - 12x < -12 + 4
x < -8
x > 8

x is greater than 8
6 0
3 years ago
You coach a basketball ball team of 12 players; 5 players must be on the floor at all times; Figuring that every player can play
makvit [3.9K]
The function "choose k from n", nCk, is defined as
  nCk = n!/(k!*(n-k)!) . . . . . where "!" indicates the factorial

a) No position sensitivity.
The number of possibilities is the number of ways you can choose 5 players from a roster of 12.
  12C5 = 12*11*10*9*8/(5*4*3*2*1) = 792
You can put 792 different teams on the floor.

b) 1 of 2 centers, 2 of 5 guards, 2 of 5 forwards.
The number of possibilities is the product of the number of ways, for each position, you can choose the required number of players from those capable of playing the position.
  (2C1)*(5C2)*(5C2) = 2*10*10 = 200
You can put 200 different teams on the floor.
4 0
3 years ago
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