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3 years ago

Why do opaque materials become warmer when light shines on them?

1 answer:

6 0

Opaque materials absorb all the light that shines on them. None of it comes out the other side. That's why they're opaque.

Opaque materials become warmer when light shines on them, because <em>they absorb the energy</em> carried by the light that shines on them. (According to the law of Conservation of Energy, that energy has gotta go somewhere.)

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The pilot of an airplane flying at an elevation of 5000 feet sights two trees that are 300 feet apart. If the angle of depressio

OLEGan [10]

Answer:

32°

Explanation:

From the diagrammatic representation of the question,

Point A is the pilot point of view from the airplane

Point C is the foot of the first tree

Point D is the foot of the second tree

Line AB is the height of the airplane from the ground level.

Line CD is the distance between the two trees

Considering ΔABC,

tan 33° $= \frac{5000}{BC}$

BC = 5000 / tan 33°

$BC = \frac{5000}{0.6494}$

BC = 7,699.41 feet

BD = BC + CD

BD = 7,699.41 + 300

BD = 7,999.41 feet

Considering ΔABD,

tan θ $= \frac{AB}{BD}$

tan θ $= \frac{5000}{7,999.41}$

tan θ = 0.6250

θ = tan⁻¹ 0.6250

θ = 32°

7 0

3 years ago

What is the momentum of a 248 g rubber ball traveling at 30.0 m/s?

Vikentia [17]

<span>The answer is, 7.44 kg*m/s</span>

4 0

4 years ago

75 points please answer ASAP what kind of enrgy is required for photosynthesis to occur

exis [7]

Solar Energy Needs To Occur

7 0

3 years ago

Read 2 more answers

A 14.0 g wad of sticky clay is hurled horizontally at a 110 g wooden block initially at rest on a horizontal surface. The clay s

ahrayia [7]

Answer:

86.53 m/s

Explanation:

Given:

Mass of clay (m) = 14.0 g = 0.014 kg

Mass of block (M) = 110 g = 0.110 kg

Initial speed of block (U) = 0 m/s

Sliding distance (d) = 7.50 m

Coefficient of friction between block and surface (μ) = 0.650

Let the initial speed of clay be 'u' and speed of clay and block just after collision be 'v'.

Now, momentum is conserved just before and just after collision.

Momentum just before collision = $mu + 0 = mu$

Momentum just after collision = $(m + M)v$

Therefore, $mu=(M+m)v$ --------- (1)

Now, using newton's second law and we find the acceleration of the system.

The frictional force is given as:

$f=\mu mg=-ma\\\\a=-\mu g$

Now, using equation of motion, we can find the velocity just after collision.

$0^2=v^2+2ad\\\\v=\sqrt{-2ad}\\\\v=\sqrt{-2\times (-\mu g)\times d}\\\\v=\sqrt{2\mu gd}$

Plug in the given values and find 'v'. This gives,

$v=\sqrt{2\times 0.650\times 9.8\times 7.50}\\\\v=\sqrt{95.55}=9.77\ m/s$

Now, using equation (1) and substituting the given values, we get:

$0.014u=(0.014+0.110)\times 9.77\\\\u=\frac{0.124\times 9.77}{0.014}\\\\u=86.53\ m/s$

Therefore, the speed of the clay immediately before impact is 86.53 m/s.

7 0

3 years ago

The electrical generators can provide 1.5 × 109 W of power for a maximum of 5 hours. Calculate the maximum energy that can be tr

hoa [83]

The maximum energy that can be transferred by the electrical generator is 2.7×10¹³ Joules.

We can use the equation of electric power and electric energy.

Electric Power: This can be defined as the ratio of the electric energy to the time of electrical equipment.

⇒ Formula

P = E/t............... Equation 1

⇒Where:

P = Maximum electric power
E = Maximum electric Energy
t = time.

make E the subject of the equation

E = Pt................. Equation 2

From the question,

⇒ Given:

P = 1.5×10⁹ W
t = 5 hours = (5×60×60) seconds = 18000 seconds = 1.8×10⁴ s

⇒ Substitute these values into equation 2

E = (1.5×10⁹)(1.8×10⁴)
E = 2.7×10¹³ Joules.

Hence, the maximum energy that can be transferred by the electrical generator is 2.7×10¹³ Joules.

Learn more about Electric energy here: brainly.com/question/21222010

3 0

3 years ago

Read 2 more answers