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puteri [66]
4 years ago
6

What form does nitrogen take in the atmosphere?

Chemistry
1 answer:
creativ13 [48]4 years ago
4 0

Answer:

N2

Explanation:

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What is the pH of a 1.288 M solution of sodium acetate? Ka of acetic acid is 1.8*10^-5. (2 decimal places)
Shtirlitz [24]

Answer:

The pH of the solution is 9.43

Explanation:

sodium acetate = CH3COONa

after removing the spectator ion Na

CH3COO⁻ + H2O ⇄ CH3COOH + H3O⁺

since sodium acetate is a weak base, it will not react completely with water. Thus a value "x" will be used to make the products.

At equilibrium:

[CH3COO⁻] = 1.288 - x

[CH3COOH] = x

[H3O⁺] = x

Since a base is reacting with H2O, Kb is used at equilibrium: Kb=(1*10^-14)/(1.8*10^-5) = 5.6*10^-10)

Kb = [CH3COOH][H3O⁺]/[CH3COO⁻]

Kb = (x²)/(1.288-x) since the Kb is significantly lower than 1.288 we can make a mathematical assumption that x is significantly lower than 1.288.

5.6*10⁻¹⁰ = x²/1.288

x = [OH⁻] = 2.675*10⁻⁵ M

pOH = -log[OH⁻] = 4.57

pH=14-pOH = 14 - 4.57 = 9.43

4 0
3 years ago
At a certain temperature, the ph of a neutral solution is 7.78. what is the value of kw at that temperature? express your answer
Strike441 [17]
Given the pH of the solution, we can determine [H⁺]. 

pH = -log[H⁺]
[H⁺] = 10⁻⁷·⁷⁸
[H⁺] = 1.659586907 x 10⁻⁸ M

We also know that pOH = 14 - pH. Thus, the pOH is  6.22. Given the pOH of the solution, we can determine [OH⁻]. 

pOH = -log[OH⁻]
[OH⁻] = 10⁻6.22
[OH⁻] =  6.02559586 x 10⁻⁷ M

The ionic product of water Kw, can then be calculated using the following equation.

Kw = [H⁺][OH⁻]
Kw = (1.659586907 x 10⁻⁸)(6.02559586 x 10⁻⁷)
Kw = 1.0 x 10⁻¹⁴
8 0
4 years ago
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