The sum of the mass numbers and the sum of the atomic numbers balance on either side of an equation
A chemical equation is your answer. Please correct me if I am wrong.
Having a definite volume but not a definite shape.
Answer:
The pH of the solution is 9.43
Explanation:
sodium acetate = CH3COONa
after removing the spectator ion Na
CH3COO⁻ + H2O ⇄ CH3COOH + H3O⁺
since sodium acetate is a weak base, it will not react completely with water. Thus a value "x" will be used to make the products.
At equilibrium:
[CH3COO⁻] = 1.288 - x
[CH3COOH] = x
[H3O⁺] = x
Since a base is reacting with H2O, Kb is used at equilibrium: Kb=(1*10^-14)/(1.8*10^-5) = 5.6*10^-10)
Kb = [CH3COOH][H3O⁺]/[CH3COO⁻]
Kb = (x²)/(1.288-x) since the Kb is significantly lower than 1.288 we can make a mathematical assumption that x is significantly lower than 1.288.
5.6*10⁻¹⁰ = x²/1.288
x = [OH⁻] = 2.675*10⁻⁵ M
pOH = -log[OH⁻] = 4.57
pH=14-pOH = 14 - 4.57 = 9.43
Given the pH of the solution, we can determine [H⁺].
pH = -log[H⁺]
[H⁺] = 10⁻⁷·⁷⁸
[H⁺] = 1.659586907 x 10⁻⁸ M
We also know that pOH = 14 - pH. Thus, the pOH is 6.22. Given the pOH of the solution, we can determine [OH⁻].
pOH = -log[OH⁻]
[OH⁻] = 10⁻6.22
[OH⁻] = 6.02559586 x 10⁻⁷ M
The ionic product of water Kw, can then be calculated using the following equation.
Kw = [H⁺][OH⁻]
Kw = (1.659586907 x 10⁻⁸)(6.02559586 x 10⁻⁷)
Kw = 1.0 x 10⁻¹⁴
