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ladessa [460]
3 years ago
15

A barrel contained 70 gallons of water. Water leaked out of the barrel at a rate of 5 gallons every 3 days.

Mathematics
1 answer:
Ainat [17]3 years ago
3 0

Answer:

42 days

Step-by-step explanation:

Given

Gallons = 70

Leakage = 5 gallons in 3 days

Required

Determine the number of days it finish leaking out

The scenario can be represented as:

5 gallons = 3 days

and

70 gallons = x

Where x represents the number of days to leak out 70 gallons

Cross Multiply:

5 * x = 3 * 70

5 x = 210

Divide both sides by 5

x = \frac{210}{5}

x = 42

<em>Hence, it'll take 42 days</em>

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The first step in any problem is to look at what you are given. When solving systems of linear equations, it is often helpful to eliminate one or more of the variables by adding or subtracting a multiple of one equation with a multiple of another. It is convenient when at least one of the multipliers is 1.

Here, we can cancel the y-terms in the 2nd and 3rd equations simply by adding them together. This gives

... (5x +y -4z) +(-3x -y +5z) = (41) +(-45)

... 2x +z = -4 . . . . simplified

Likewise, we can add 3 times the second equation to the first to cancel y in that sum.

... 3(5x +y -4z) +(2x -3y +z) = 3(41) + (-1)

...15x +3y -12z +2x -3y +z = 123 -1

...17x -11z = 122 . . . . simplified

Now that we have 2 equations in x and z, we can go through the same process. We observe that the coefficient of z is +1 in the first equation and -11 in the second. The means we can cancel the z terms by adding 11 times the first equation to the second:

... 11(2x +z) +(17x -11z) = 11(-4) +122

...22x +17x = 78 . . . . . . simplify a little bit

... x = 78/39 = 2 . . . . . . divide by 39

From above, we find

... z = -4 -2x = -4 -2·2 = -8

... y = 41 -5x +4z = 41-5(2) +4(-8) = 41 -42 = -1

The solution is (x, y, z) = (2, -1, -8).

_____

The method of elimination used here will vary with the system of equations. If you want to employ a consistent method, you can use Cramer's Rule, Gaussian elimination, or matrix methods. Since you apparently don't mind help from technology, learning to do this on your graphing calculator can also be a good idea.

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