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Eva8 [605]
3 years ago
13

Help me pls thanks so much

Mathematics
1 answer:
3241004551 [841]3 years ago
3 0

Answer: The angle is 35 is specifically 34.85

Step-by-step explanation:

sin^{-1}(\frac{8}{14})=34.85

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Determine weather randomly picking a blue card from a bag containing all blue cards is impossible, unlikely, as likely as not, l
Anuta_ua [19.1K]

Answer:

The correct answer is certain with probability equal to 1.

Step-by-step explanation:

Probability is a mathematical framework which helps us to analyze chance of the outcome in a particular experiment. The value of probability is given by the ratio of the possible outcomes favorable to a certain experiment to the total outcomes.

We say an event is certain when the probability is 1 and the probability is zero when the event is uncertain.

Here the experiment is picking a blue card from a bag containing all blue cards.

Possible outcomes are all the cards colored blue in the bag.

Total outcomes are also all the blue cards in the bag.

∴ The value of probability is 1 as the event is certain because if we pick a card from the bag containing only blue cards, it would certainly give us a blue card.

5 0
2 years ago
Hey guys please help with this questoin Find (x+y) ÷ (x-y) if x=5/4 y=-1/3​
pogonyaev

Answer:

<h2>11/19</h2>

Step-by-step explanation:

(\frac{5}{4} + (-\frac{1}{3})) \div (\frac{5}{4} - (-\frac{1}{3}))\\\\\frac{\frac{5}{4}+\left(-\frac{1}{3}\right)}{\frac{5}{4}-\left(-\frac{1}{3}\right)}\\\\\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a,\:-\left(-a\right)=a\\=\frac{\frac{5}{4}-\frac{1}{3}}{\frac{5}{4}+\frac{1}{3}}\\\\\mathrm{Join}\:\frac{5}{4}+\frac{1}{3}:\quad \frac{19}{12}\\\mathrm{Join}\:\frac{5}{4}-\frac{1}{3}:\quad \frac{11}{12}\\\\=\frac{\frac{11}{12}}{\frac{19}{12}}\\\\=\frac{11\times\:12}{12\times \:19}

= 11/19

7 0
3 years ago
How do you work this out?
Katarina [22]
Because ABCD is a rectangle, the length of CD is 12 cm.

We need to determine the length of DE.  If we can do that, then the sum of the lengths of CD and DE represents the unknown:  the length of CE.

To find the length of CE, we have to "solve" the upper triangle.

Here's an outline of what to do:

1.  Show that BC=AD and find the length.
2.  Note that angle CAD is 60 degrees.  Why?
3.  Note that angle EAD is 30 degrees.  Why?
4.  Find the length of ED
5.  Add ED and DC, that is, ED + 12 cm.  This is your answer.

Please ask questions if need be.
5 0
2 years ago
Make a dot plot for each set of data. Compare and contrast the shape, spread, and center of the data.
jeka94

Set A has a peak at 5. It is also skewed to the right. The center is 5.

Set B also has a peak at 5. Is relatively symmetrical. The center is also 5.

(Sorry about those circle in the back of my picture)

6 0
2 years ago
Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (
Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

P(\frac{T}{S}) = 0.95

P(\frac{T}{S^c}) = 0.05

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

P(S^c) =  1 - P(S)

= 1 - 0.3

= 0.7

ii. P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}

= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }

= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}

= 0.8906

iii. P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}

= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }

= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}

= 0.0221

We simply applied the above formulas so that the each part could come

8 0
2 years ago
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