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romanna [79]
3 years ago
11

Safety is a concern around electronic equipment of all types. What particular safety hazard may exist A. Laser light B. High vol

tage C. Delicate equipment D. Radioactivity
Chemistry
1 answer:
omeli [17]3 years ago
7 0
All of the above. If you are going to narrow it down, it would be high voltage and radioactivity.
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Aluminum oxide is formed when aluminum combines with oxygen in the air. How many grams of Al2O3 are formed when 13.6 mol of Al r
LenKa [72]

Answer:

4Al + 3O2 → 2Al2O3 a. If you use 2.3 moles of Al, how many moles of Al2O3 can ... How many grams of Al2O3 are produced from the reaction of 5 moles of Al?

Explanation:

3 0
3 years ago
A block of pine wood has a mass of 120 g and a volume of 300 cm3. What is the density of wood? (Show your work)
Zielflug [23.3K]

Answer:

The answer is

<h2>0.4 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}

From the question

mass of wood = 120 g

volume = 300 cm³

So the density of the wood is

density =  \frac{120}{300}  \\  =  \frac{12}{30}  =  \frac{2}{5}

We have the final answer as

<h3>0.4 g/cm³</h3>

Hope this helps you

5 0
3 years ago
Which of the following is not a method of heat transfer?
abruzzese [7]
The answer is adduction lol
8 0
3 years ago
C2h4 3 o2 2 co2 2 h2o
Marat540 [252]
Use the question marck Moles of CO2
The the giving = 0.624 mol O2
Find the CF faction = 1 mole=  32.00 of O2

O= 2x16.00= 32.00amu ( writte this in the cf fraction)
SET UP THE CHART
Always start with the giving

0.624 mol O2    /  1mol of CO2
___________  / _____________ = Cancel the queal ( O2)
                       / 32.00c O2
                      /
                     /
Multiply the top and divide by the bottom 
0.624 mol CO x 1mol CO2 = 0.624 divide by 32.00 O2 =0.0195
You should look at the giving number ( how many num u gor ever there) 
Ur answer should have the same # as ur givin so 
= 0.0195 
= .0195 mol of CO2
3 0
3 years ago
What were the limitations of Newlands Law of Octaves.?<br><br> No spam ❌❌<br> or else (-_-メ)​
liubo4ka [24]

Answer:

The major limitations of Newlands' law of octaves were : (i) It was applicable to only lighter elements having atomic masses upto 40 u, i.e., upto calcium. After calcium, the first and the eighth element did not have similar properties

5 0
3 years ago
Read 2 more answers
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